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Basic Physics

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Thread replies: 9
Thread images: 2

File: IMG_0471.gif (3KB, 486x256px) Image search: [Google]
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Hey /sci/, brainlet here.

In physics we know that acceleration is the change in velocity over time. Yet I've see some weird formulas for finding acceleration such as pic related.

Is there any intuitive way to conceptualize why acceleration is equal to the change in velocity over twice the distance? Why does this work when the denominator is time AND when it is 2(d)? Why are we multiplying d by 2 in the first place?
>>
>>8591377
Whoops. Meant d^2 not 2d.
But here is 2delta(d) in the denominator.

How is it that we can solve for the same variable (acceleration) using different denominators in (what would have been) the same equation?
>>
>>8591377
That's... totally wrong. Units don't work.
>>
File: IMG_0472.png (3KB, 229x122px) Image search: [Google]
IMG_0472.png
3KB, 229x122px
>>8591381
>forgets to post pic
I really need to get my shit together
>>
>>8591377
Take calc 1 and learn how to differentiate/integrate basic polynomials.
Algebra-based physics is a shitty meme
>>
>>8591377
>constant acceleration
x=xi+vi*t+a*t^2/2
v=vi+a*t

d=xf-xi
vf-vi = a*t
t=(vf-vi)/a

d=vi*t+a*t^2/2
d=vi*(vf-vi)/a+a*((vf-vi)/a)^2/2
d=vi*(vf-vi)/a+(vf-vi)^2/2a
a*d=vi*(vf-vi)+(vf-vi)^2/2
a*d=vi*vf-vi^2+(vf^2-2vf*vi+vi^2)/2
a*d=-vi^2+(vf^2+vi^2)/2
a*d=(vf^2-vi^2)/2
a=(vf^2-vi^2)/2d
>>
>>8591377
> Yet I've see some weird formulas for finding acceleration such as pic related.

It helps to have a legitimate equation to start with..

Even with your correction, it is still invalid, see:>>8591383
Also it is genuinely tough to understand mechanics intuitively without using and understanding calculus to second >>8591386
>>
Here's the problem that I need to solve:

Pam, wearing a rocket on her back, stands on frictionless ice. Her mass is 45kg. The rocket supplies a constant force for 22 meters and Pam acquires a speed of 62 m/s.

1) What is the magnitude of the force
2) What is Pam's final Kinetic Energy?

I think for part 2 it's a bit easier since you just plug in the mass and velocity into the KE =(1/2)mv^2.
But for the first part you would need to work out acceleration, no?

We know the initial velocity is zero and the final velocity is 62 m/s. We know the distance that was traveled and we know her mass.
How do we find Force?
>>
>>8591390
>How do we find Force?
See >>8591383
Thread posts: 9
Thread images: 2


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