i'm a fag

About 2.485

>>8582722
3sin (1/pi)

>>8582756
i meant (1/4)pi

r+r*sqrt(2)=6

>>8582722
Take the diagonal radius of the big circle.

6 = r + r * sqrt(2)

r = 6 / (1 + sqrt(2)) = 2.485, which is what >>8582747 said

>>8582764
where does the sqr(2) come from

>>8582758
Actually I'm wrong didn't look at the pic

File: MFHi5.jpg (19KB, 959x719px) Image search: [Google]

19KB, 959x719px

>>8582773

the diagonal part

>>8582813
I don't get it

File: unnamed.jpg (38KB, 738x984px) Image search: [Google]

38KB, 738x984px

>>8582764
>>8582747
These are correct. I took a coordinate geometry approach that was probably a bit overkill

>>8582859
After looking at what I did and comparing it to this
>>8582813
>>8582764
I realize what a fag I am for not seeing simple geometry

File: 1483656020007s.jpg (10KB, 250x202px) Image search: [Google]

10KB, 250x202px

>>8582722
imagining the red line i got 6/sqrt(2)/(1+sqrt(2)/2) without even using a piece of paper

>>8582844
The rightmost "r" is at an angle of 45 deg, 6-r-r*sin(45 deg) = 0.

>>8582722
About three fifty

>>8582859
>>8583248
How do you prove it's 45*

File: wat.png (21KB, 385x298px) Image search: [Google]

21KB, 385x298px

are you all retarded or am I?

How is 6 not more than 2r

>>8583618
Are you serious? It starts at the radius and bisects the 90 degree angle between the bottom and side.

>>8583701
>starts at the radius
I mean starts at the center of the circle.

>>8583693
ok yeah im retarded

File: topologicallyafaggot.png (22KB, 960x540px) Image search: [Google]

22KB, 960x540px

in other words, its is not possible because radius of a smaller circle can't be >=6.

>>8584668
>it's impossible for a circle to fit inside a quarter of a circle
Also, I can't read your = arcsin(?) part, so I can't tell what error you've made.

File: 1483553867154.jpg (35KB, 720x460px) Image search: [Google]

35KB, 720x460px

6/(1+φ)= 2.29179

noobs

File: 1483614465626.png (470KB, 840x824px) Image search: [Google]

470KB, 840x824px

>>8585657
6/(1+√2)=2.485281