so let me get this straight. If the graviton is real, then it is a ripple in the gravitational field.
However, if the graviton and supersymmetry are both real, there's a gravitino that is a ripple in the gravitino field.
If the gravitational field is spacetime, then what is the gravitino field?
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>>8579722
In supergravity, the gauge field for graviton is the vielbien (the "square root" of the metric tensor). The field for the gravitino is then a spinor field with a # of propagating fermionic degrees of freedom to match the # of propagating bosonic degrees of freedom of the graviton. The fields are related via local supersymmetry transformations.
>>8579779
I don't know what that means. Can you dumb it down for me?
>>8579725
I appreciate you.
>>8579782
Supersymmetry, physically, is essentially the requirement for a theory to have equal amounts of bosonic and fermionic degrees of freedom.
i.e. Each bosonic/fermionic particle has a fermionic/bosonic "superpartner".
Generally these are related to each other through a supersymmetry transformation.
The graviton does correspond to spacetime itself, but the gravitino is just its fermionic superpartner. It is just some fermionic field and only related to spacetime geometry via a supersymmetry transformation mapping it to its superpartner.
>>8579809
That makes it sound like the gravitino field is completely unrelated and is just a random particle field
>>8579725
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>>8579823
It is not completely unrelated, it is the supersymmetric "dual" of the graviton. It is not, in general, significant beyond that.
>>8579845
So otherwise space and time are completely identical?
>>8579847
Spacetime in supergravity theories (and string theories), while maybe varying in dimension and geometry depending on the specific theory, are otherwise the same as spacetime in regular theories.
The supersymmetry is not something applied to the spacetime manifold itself, but to its algebra of functions.