Could /sci/ help me find the area of this?

File: 14815788889861905782252.jpg (2MB, 5376x3024px) Image search: [Google]

2MB, 5376x3024px

And this

Bump, I'm looking to solve it.

>>8534646
you have the base and height of a triangle which is 1/6th of the total triangle

>>8534653
you have the base and height of a triangle which is 1/12th the area of the hexagon

post your shit in the stupid questions thread idiot

>>8534646
Multiply the radius by the base, divide that by two, then multiply by three. You can cut that triangle into 3 equal parts can't you?

Then yeah

Is the first triangle equilateral ? Because if that is the case, it should be a piece of cake, and same thing for the second one (if it's a regular polygon).

>>8534646
Imagine that length went all the way through the triangle, it would create a pair of right triangles with the hypotenuse and long side known. Because it's equilateral you know that all the angles are 60 and when you cut it up you get two 30 60 90 triangles.

(Hint the bisector piece is 1/3 of the total length of the total bisector)

You do a similar thing for the second one, just make a bunch of triangles (there's an easier way to do it, but I haven't done geometry in something like 8 years)

>>8534646
The area is -1/12