How would you re-arrange an equation like this for x?

File: Photo 05-12-2016, 8 55 49 pm.jpg (211KB, 1280x722px) Image search: [Google]

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Further more: does..

>>8517911
Well first, for any x you have sin(x) = sin(x + 2kpi), so sin(x-90) = sin(x - 90 + 2kpi)

So basically you can already simplify it a bit.

Then you have cos(x)*sin(x), which is sin(2x) - cos(x)*sin(x)

>>8517911
does that have cos(x-90) or cos(x * 90) in the denominator

>>8517923
cosine x minus 90, sorry

>>8517911
[math] \cos ( x - 90 ) = \sin ( x ) [/math] likewise [math] \sin ( x - 90 ) = - \cos ( x ) [/math] so [eqn] - \cos ^2 ( x ) = \frac { 1 } { 16 } [/eqn]

>>8517928
>Assuming degrees

>>8517914
No

>>8517928
okay! awesome!

>>8517937
>Being a faggot.

>>8517928
from here how would you use cosine inverse on the squared cosine?

>>8517949
>Unironically liking women

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>>8517911
Here's the question it came from

>>8517928
shouldn't this just be an even cos because of even-odd identities?

>>8517911
>>8517928
In general, you just have to pray that you can find a trig identity to simplify the expression.

>>8517959
40sin(a)-xcos(a)=0
40cos(a)+xsin(a)=100
1600cos^2(a)+80xcos(a)sin(a)+x^2sin^2(a)=10000
1600sin^2(a)-80xcos(a)sin(a)+x^2cos^2(a)=0
1600+x^2=10000
x^2=8400
x=91.65 N
40sin(a)=91.65cos(a)
tan(a)=2.29
a=66.42

>>8517926
your handwriting is shit OP

>>8517955
->greentexting

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