[Boards: 3 / a / aco / adv / an / asp / b / bant / biz / c / can / cgl / ck / cm / co / cock / d / diy / e / fa / fap / fit / fitlit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mlpol / mo / mtv / mu / n / news / o / out / outsoc / p / po / pol / qa / qst / r / r9k / s / s4s / sci / soc / sp / spa / t / tg / toy / trash / trv / tv / u / v / vg / vint / vip / vp / vr / w / wg / wsg / wsr / x / y ] [Search | Free Show | Home]

How do I prove this?

This is a blue board which means that it's for everybody (Safe For Work content only). If you see any adult content, please report it.

Thread replies: 26
Thread images: 1

File: proveit.jpg (6KB, 462x162px) Image search: [Google]
proveit.jpg
6KB, 462x162px
How do I prove this?
>>
analytically
>>
>>8515757
What does that mean?
>>
>>8515744
It's false
>>
>>8515763
How do you know?
>>
>>8515763
where are the proofs?
>>
>>8515744
Move 4abcd to the other side of the inequality, take sqare root of both sides. This should immediately look like a familiar inequality, with minor complications.
>>
>>8515805
Why don't you just do the proof? What you said makes little sense.
>>
>>8515766
let them all equal 1 lol
>>
>>8515744
It's false, consider

a = -2b, -c/12 < d < 0
>>
divide by (b d)^2 set A=a/b, C = c/d, get
(A-C)^2 + 2 A + 2 C, and it's obvious
>>
>>8515827
>a = -2b

They're all positive.
>>
>>8515833
That's what you're supposed to prove.
>>
>>8515821
[math](1*1+1*1+1*1)^2 - 4*1*1*1*1 > 0 \\ (3)^2 - 4 > 0 \\ 9-4>0 \\ 5>0[/math]
>>
>>8515836
No, you're trying to prove the left expression given the right.
>>
>>8515830
sorry, should be
(A-C)^2 + 2 A + 2 C + 1 > 0
where A = a/b, C=c/d. Still obvious.

The original expression is just
((a/b-c/d)^2 + 2 a/b + 2 c/d + 1)*(b d)^2 >0
>>
>>8515812
I'm not doing your homework, you fucking mongoloid. Do exactly what I said. It's a simple application of AM-GM.
>>
>>8515744
Move 4abcd to the right hand side, expand the term in parentheses, then do some algebra and you should be fine.

But your statement is meaningless. What numbers am I allowed use? It isn't true if I can use negatives.
>>
>>8515841
you can replace a,b,c,d>0 with the weaker condition
a/b + c/d > 0
>>
>>8515830
I think you've done it my friend. Thanks.
>>
>>8515744
Get a really big computer and try all combinations of numbers smaller than 10^200, easy proof. This is how the goldbach conjecture was proven.
>>
>>8515744
https://www.wolframalpha.com/input/?i=(a+d+%2B+b+c+%2B+b+d)%5E2+-+4+a+b+c+d+%3E+0

print this out and hand it to your teacher
>>
(ad + bc)^2 - 4abcd > 0 is true when a,b,c,d > 0
>>
>>8515744

(ad + bc + bd)^2 - 4abcd > 0

root ((ad + bc + bd)^2) >root( 4abcd)

(ad + bc + bd)^2 >2root(abcd)

Onli if a,b,c,d>0
>>
>>8515990

ad + bc + bd >2root(abcd)

Only if a,b,c,d>0
>>
>>8515821
You retard lmao
Thread posts: 26
Thread images: 1


[Boards: 3 / a / aco / adv / an / asp / b / bant / biz / c / can / cgl / ck / cm / co / cock / d / diy / e / fa / fap / fit / fitlit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mlpol / mo / mtv / mu / n / news / o / out / outsoc / p / po / pol / qa / qst / r / r9k / s / s4s / sci / soc / sp / spa / t / tg / toy / trash / trv / tv / u / v / vg / vint / vip / vp / vr / w / wg / wsg / wsr / x / y] [Search | Top | Home]

I'm aware that Imgur.com will stop allowing adult images since 15th of May. I'm taking actions to backup as much data as possible.
Read more on this topic here - https://archived.moe/talk/thread/1694/


If you need a post removed click on it's [Report] button and follow the instruction.
DMCA Content Takedown via dmca.com
All images are hosted on imgur.com.
If you like this website please support us by donating with Bitcoins at 16mKtbZiwW52BLkibtCr8jUg2KVUMTxVQ5
All trademarks and copyrights on this page are owned by their respective parties.
Images uploaded are the responsibility of the Poster. Comments are owned by the Poster.
This is a 4chan archive - all of the content originated from that site.
This means that RandomArchive shows their content, archived.
If you need information for a Poster - contact them.