Headphone efficiency

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Anonymous
Headphone efficiency 2016-12-01 23:41:55 Post No. 8509634
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Headphone efficiency Anonymous 2016-12-01 23:41:55 Post No. 8509634 [Report]

I'm in a Physics of Music course right now and we're doing some projects at the moment. I'm currently trying to determine the efficiency of a pair of headphones.

How I would calculate it would be

η= (Power_out) / (Power_input)

What I can't seem to find is the power output of the headphones at a certain distance. I know the power input of a headphone jack is something like 10-20mW (please correct me if that's wrong) so that's the value I would use to calculate.

Any help anons?

Anonymous 2016-12-01 23:57:16 Post No.8509660
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Anonymous 2016-12-01 23:57:16 Post No.8509660 [Report]

You would probably have to physically measure the amount of sound coming out of the headphones

Anonymous 2016-12-02 00:01:21 Post No.8509669
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Anonymous 2016-12-02 00:01:21 Post No.8509669 [Report]

>>8509660
I've been using the estimate that it is 90dB at 4.5cm

Anonymous 2016-12-02 02:27:13 Post No.8509879
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Anonymous 2016-12-02 02:27:13 Post No.8509879 [Report]

>>8509669
Calculate the 3d wave decay whatever

Anonymous 2016-12-02 02:27:44 Post No.8509880
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Anonymous 2016-12-02 02:27:44 Post No.8509880 [Report]

>>8509879
Sick guess I'll go fuck myself

Anonymous 2016-12-02 02:38:40 Post No.8509899
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Anonymous 2016-12-02 02:38:40 Post No.8509899 [Report]

>>8509634
Get a sound meter and measure the distance between the speaker cone and the diaphram of the mic. Cost's like $50 at Home Depot tho

Anonymous 2016-12-02 03:35:53 Post No.8509988
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Anonymous 2016-12-02 03:35:53 Post No.8509988 [Report]

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>>8509899
So what I've done is the following:
Find the decibels of the threshold of hearing at this radius (4.5cm) and then take this and apply it as SIL 1 and 90dB as SIL 2. Then find the intensity of the 90dB at the same radius. Convert this intensity to Power_Out by using the area of the sphere using the same 4.5cm radius. Then take the ratio to find efficiency.

Does pic related look correct or am I retarded?

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I'm aware that Imgur.com will stop allowing adult images since 15th of May. I'm taking actions to backup as much data as possible.
Read more on this topic here - https://archived.moe/talk/thread/1694/