Hey i can't solver this no matter what , can you guys help me?

>>8490609
Can you relate BA and AC to known quantities?

>>8490616
i know the value of both of them put together other than that this is the only info that i have
Thanks

>>8490621
Now state that information mathematically. But it's not the only information you have, it's a right triangle, which gives more information.

>>8490623
P = AB + AC + BC ?

ba^2+ac^2=25^2
ba^2+ac^2=625

next you have perimeter that is ac+ab+bc
60-25=35
ba+ac=35
20^2+15^2=625

>>8490609
AB+AC=35
25^2=AB^2+AC^2

(AB+AC=35)^2 =>
AB^2+AC^2 + 2AB*AC=35^2
25^2 + 2AB*AC=35^2
25^2 + 2AB*(35-AB)=35^2

>>8490634
Now play around with this until you can isolate what you need.

>>8490637
so now i solve it in order to to isolat AB and after i have AB i know the other value?

Ab + ac = 35
ab^2 + ac^2 = 25^2
(ab + ac)^2 -2ab.ac= 625
ab.ac = 300
ab = 35-ac
ac(35-ac)=300
ac^2 - 35ac + 300=0
ac^2-20ac -15ac +300=0
ac (ac-20) -15(ac-20) = 0
ac = 15, 20

>>8490659
thanks for the help :)