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wtf kind of sequence is this?

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Thread replies: 15
Thread images: 3

File: 35xyux.jpg (44KB, 560x641px) Image search: [Google]
35xyux.jpg
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1, 3/2, 5/6, 7/24, 9/120

i cant find a suitable a(sub n) term for n greater than or equal to 1.

numerator is odd numbers and denominator is n times the previous denominator, but how do i express this?

I tried using an induction method and systems of linear equations with
an^2+bn+c

then,
1=a+b+c
3/2=4a+2b+c
5/6=9a+3b+c

but this only gives me the first three n terms (not surprising)

halp pls
>>
that is, (-7/12)(n^2)+(9/4)n-(2/3) is a suitable formula when 1<n<3

i need a formula for all n greater than or equal to 1.

halp a brainlet. i tried four tutors and they cant solve
>>
nvm i got its 2n-1/n!

im a brainlet srry
>>
>>8481114
First term:
1/1
Second term
3/2
Third Term
5/6
Which is 2n-1/n! n E N
>>
>>8481118

is 2n-1 another way of saying odd?
>>
>>8481114
https://www.algebra.com/algebra/homework/Sequences-and-series/Sequences-and-series.faq.question.871381.html
>>
>>8481210
2n-1 is always odd for natural n

>inb4 what about n=0
>>
https://oeis.org/
>>
>>8481227
>inb4 what about n=0
so -1 is a even number then? wtf
>>
>>8481119
>Not specifying whether 0 E N or not.
>>
>>8481119
retard
>>
>>8481474
meant for this retard >>8481473
>>
>>8481473
nice mee mee
>>
File: 936.jpg (33KB, 625x626px) Image search: [Google]
936.jpg
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>>8481412
>>
>>8481114
Starting with n=1, the sequence is:
a_n = (2n - 1)/(n!), where n! is the factorial function, a function that takes the positive integers less than or equal to n, and multiplies them altogether.
Thread posts: 15
Thread images: 3


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