This is too much for the /wsr/ plebes; could u guys help me figure out the fourier transform of the following function:
g(x)=(cos(alpha*x))^2
any book recommendations for someone with non-formal knowledge of integral calculus?
cos^2(a*x)=(cos(2*a*x)+1)/2
=1/2+(1/2)*cos(2*a*x)
IOW, G(f)=1/2 if f=0 or f=a/pi and 0 otherwise.
>>8480134
>non-formal knowledge of integral calculus.
Anon, there's no easy way to say this, other than you should sit down and read about integral calculus.
http://freebookcentre.net/Mathematics/Fourier-Analysis-Books.html
Here's a good list of free books on fourier analysis.
>>8480134
You need to know integral calculus to use the Fourier transform in a naive way, but to understand Fourier theory you will need at least linear algebra and analysis.
To find the transform of that function, and to "figure out" the Fourier transform simply apply the formula (note that there are several equivalent ways of taking the transform).
[math]\mathcal{F}(f)_{k} = \frac{1}{2\pi}\int_{-\pi}^{\pi}f(x)e^{-ikx}dx[/math]
>>8480134
multiplication in time is just convolution in frequency
>>8480336
Thx anon
>>8480349
[(cos(alpha*x))^2]*[e^-ikx]