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Anonymous
A little help with physics 2016-11-09 04:22:35 Post No. 8464452
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A little help with physics 2016-11-09 04:22:35 Post No. 8464452
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Just started a new unit in physics. Might be a brainless pleb but I'm calling upon the hordes of anonymous to help me out.
A 2.00-kg mass hangs from a wire. Find the tension in the wire under an acceleration of _____
(A) 5.00 m/s^2 Up.
(B) 5.00 m/s^2 down.
Find both and explain please
>>
F=MA; Force is equal mass * accelation and so is Tension
So start by computing Acceleration and mulitply by mass
(A) a= 5-(g) because its up
(B) a= -(5+(g)) because its down
substitute g for local gravity, usually 9.82 but it can change depending how close you are to the Ecuator
So (A) 2[kg] * (5-9.82)m/s^2 = -9.64N
and(B) is -28.64[N]
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Haaaa... Glock-amole.
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>>8464460
(B)-29.64[N]* typo
>>
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>>8464460
You, my friend, are a saint among men
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>>8464452
.jpeg "Glockamole"? C'mon now that came right to me
>>
Let's consider the acceleration due to gravity be 9.8 m/s^2. So in the first case, imagine you are on the block moving upward. Hence a pseudo force is acting on the body downwards. Hence tension=m(a+g).
2(5+9.8)=29.6N. for the second case the the pseudo force will be upwards. Tenaion=9.6N
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