9/10 Facebook users can't even

>>8462082
the main "joke" of these cancer riddles is using undefined notation like two overlapping horseshoes in one place and a single horseshoe in another. This is perfectly doable with the four pictures interpreted as variables, so you failed miserably, OP.

>>8462082

Ridiculous

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>>8462088

>>8462082
The bottles = 10 each.
Burgers = 5
Booze = 2.

* (Tan-1*5/x)
S (-------------) * dx
* (x*ln(2)^10)

>>8462104
This is what I got too. But it's an indefinite integral, so I don't know how we're expected to come up with a final value.

but we haf noot defined nick cage

>>8462103
You don't really seem to get what I'm saying.

>>8462104
lrn 2 LaTeX

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>>8462104
>S (-------------)
Get the fuck out

>>8462104
\begin{document}
\frac{Tan-1*\big(5\div{x}){x*\ln{2}\^{10}}}

\end{document}

Testing

>[math] \displaystyle \int \frac{\tan^{-1}\frac{}{}}{\ln()^}d [/math]

>>8462572
>>8462674
EPIC FAIL

>>8462139

it's not asking for a value it's just asking for the answer

File: dontforgettoaddcoconut.png (17KB, 637x170px) Image search: [Google]

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ez

>>8462082
>differential of a constant

wat

>>8463257
Oh wait I'm retarded. It's not too bad then, it just doesn't have any limits. No biggie, just don't forget that C

>>8463261
>it just doesn't have any limits

It's called an anti derivative, freshie.

>>8463262
pls no bully

>>8462104

That's the way, shit on all these latex fags

>>8463239
That should all be multiplied by [math]\frac{1}{\ln(2)^{10}}[/math].

>>8462104
F U C K L A T E X

>>8463239
what is Li?

>>8463665
Li_2 is the second order polylogarithm function

>>8463686
that's pretty lit desu

I need some 4x4 mm stickers showing Nic Cage's face so I can use them as variable names on my next exam.

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How about this one? Bit simpler, going to see which of my normiebook friends can figure it out. Most of them got their a levels so I hope at least some can.

>>8463789
what's there to solve here? the answer is clearly burger

>>8463799
You're supposed to find out what number burger corresponds to.

>>8463956
Go on.
Hint: [math]\arg(a \cdot e^{i\phi}) = \phi[/math]

>>8463799
>>8463802
>>8463789
>>8463963

https://www.wolframalpha.com/input/?i=%5Cint_(-1)%5E(+1)+sin(x+%2Barg(-1)+)dx

>>8463789
[math]\int_{-1}^1\sin(x + \pi)dx = - \int_{-1}^1\sin(x)dx = \int_{0}^{-1}\sin(x)dx - \int_0^1\sin(x)dx = 0[/math]