How do you calculate the blue area if this shape is symmetrical horizontally and vertically with a square sorrounding it and knowing the middle lines are equally long? The dotted lines are not a part of the shape. I always fail at calculating the "smaller trapezoid" (green).
x = sides of square
y = lines we know are equally long
>>8444327
x^2+xy-xh-yh
where h - height of smaller trapezoid
>>8444330
fuck, I messed up
(x^2+xy)/2-(xh+yh)
let it be so, then
>>8444332
I wasn't quite sure whether I'm allowed to introduce h as height, without calculating it from the given variables. But I guess there's no other way.(?) Just wanted to dubble check.
The whole thing - white bits - green bits = the blue bits
>>8444342
>at_last_I_truly_see.png
>>8444342
I understood that, but the green bits was what made my head hurt.
>>8444327
Er, what's the trick to calculate green area?
>>8444337
h is variable. There is nothing that determines h in the shape. It appears that h=x/4 but it could be anything between 0 and x/2 if the shape is not drawn to scale, which you should always assume.
Is that Hofstadter's butterfly?
>>8444353
Exactly what I was thinking, but there has to be a solution.
Does anyone have an idea where to start proving it as calculatable?
>>8444367
either solution if variable or h=x/4
>>8444412
leave the proof as an exercise for reader ;)
>>8444337
H = (x-y)/2