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Name that function.

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Thread replies: 15
Thread images: 3

File: Untitled-1.png (14KB, 1085x671px) Image search: [Google]
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Name that function.
>>
>>8431754
looks like you've taken the bottom/top half of a sine curve (per cycle) and rotated it 45 deg. Also top half for x less than 0. Guessing you could assemble that using modulus functions and some matrix rotations
>>
F(x)

/thread
>>
>>8431757
What makes you call it an antiderivative, HMMMMMMMMMMMMMM?
>>
F is just an arbitrary letter. If youre triggered by this particular letter, there are plenty of other choices. You could even go Greek.
>>
>>8431767
Lambda (psi)
Hue
>>
>>8431754
Easy.
[eqn]
f(x) = \begin{cases}
\sin(x) + x & \text{for } x \sin (x) < 0 \\
\sin(x) & \text{for } x \sin (x) \ge 0
\end{cases}
[/eqn]
You can probably write it in one line using Heaviside functions:
[eqn] f(x) = \sin(x) + \Theta( -x \sin (x) ) x [/eqn]
>>
It's sin[x] mod x
>>
>>8431754
It's gay shit like this that mathematicians try to defend why we need analysis when really it's just children jerking off to boring garbage.
>>
>>8431754
Oh shit it dat function
>>
File: 7y9yu9958.png (1MB, 1080x1920px) Image search: [Google]
7y9yu9958.png
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But that's obviously Gödel's Incomplete Wurstline!
>>
>>8431754
In general that's impossible.
>>
File: f(x).png (54KB, 959x588px) Image search: [Google]
f(x).png
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>>8431754
That is [math]\sin \left(x\right)-\operatorname{ceil}\left(\sin \left(\left|x\right|\right)-1\right)x[/math]

Try figuring out this one. It's pretty similar
>>
>>8431858
Insecure retard biologist spotted

Oh wait, "retard biologist" is redundant.
>>
>>8432279

A formatting note: the ceiling function's bracket notation can be implemented in TeX using \lceil and \rceil, viz.

[math] \sin(x)− \lceil \sin|x|−1 \rceil x [/math]

As a corresponding example, \lfloor and \rfloor can be used to give the floor function's bracket notation, as for example in this amusing finite sum which states that the first gross, or 144 decimal digits of π (not including the leading integer part of 3) expressed in base 10 (that is, in the usual way) sum to precisely 666:

[math] \displaystyle \sum_{k=1}^{144} \lfloor 10^k \pi - 10 \lfloor 10^{k-1} \pi \rfloor \rfloor = 666[/math]
Thread posts: 15
Thread images: 3


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