>>8400563
x=x+1
x+1=x
(x+1)-1=x-1
x=x-1
>>8400563
[math]\{x \in \mathbb{C} \ | \ x = x + 1\} = \emptyset[/math]
x=x+1 (mod 1)
>>8400563
x =/= x+1
that was easy
>>8400563
x=x+1
x=(x+1)+1
x=((((x+1)+1)+1)+1)+1
x=x+n
alt:
x=(x+1)
x=x
alt:
x=x+1
(x^2)=(x^2)+2x+1
-1=2x
x=x+1
>x=0
>0=1
>So x=/=0
xº=(x+1)º
1=1
So x∈R if x=/=0
Y(Succ)
>>8400563
/g/ here.
x = x + 1;
x += 1;
x++;
Get on my level faggots.
>>8400634
>/g/
>simple python operation
As expected.
>>8400563
-1/12
x = Aleph Naught
x = + infinity or -infinity if were working over the extended reals
>>8400642
>thinks x++; is specificaly a python operation
>ignores that pretty much every language uses the same shorthand for increment
As expected
>>8400698
Thanks for the info.
Which p.language is more useful tho?
>>8400563
x=x+1
x=(x+1)+1
x=((x+1)+1)+1
x=x+2+1
repeat three more times
x=x+3+2+1
continuing in this fashion,
x=...+3+2+1
x=-1/12
x=x+1
x^2=x(x+1)
x^2=x^2 + 2x + 1
0=2x+1
-1=2x
x=-1/2
>>8400805
>-1/2 = -1/2 + 1
your x is actually |x|
>>8400642
>python
>semicolon
>>8400763
kek'd
>>8400563
[eqn]x=\sum^\infty 1[/eqn]
>>8400805
Are you high?
>x^2=x(x+1)
>x^2=x^2 + 2x + 1
x^2=x(x+1)
x^2=x^2 + x
Think i just fell for bait
>>8400642
There's no semicolons in python
>>8400634
Pretty sure there's more
++x;
x=x++;
But not
x=++x;
Right?
>>8401011
No he just skipped a step
x(x+1)=(x+1)(x+1)=x^2+2x+1
>>8400573
Stop assuming [math]x[/math]'s domain, or the definition of [math]=[/math] and [math]+[/math].
TRIGGERED
>>8400682
We're not.
>>8400563
The answer is 2.
>>8400713
Z3 is superior for shitposting.
>>8401441
>not using superior Java
>>8400563
literally just no solutions
not very hard
>>8401451
There were "literally just no solutions" to sqrt(-1) unless maths evolved.
Give it time.
>>8400563
that's just how you increment a number in like any basic programming language
>>8401457
i know a good bunch of math that proves this iterative function does not converge
>>8400563
>8400563
[math]\frac{-1}{12}[/math]
>>8400563
[eqn]\infty = \infty + 1[/eqn]
;)
This kind of thing again? Pic related.
x=x+1
8x=8x+8
0=8
Now stroke the equation vigorously.
0======8
>>8401393
says who?
>>8401885
Best solution
>>8401885
[math]-\infty = -\infty + 1[/math]
:6)
>>8400563
CHRISTINA! I DON'T HAVE TIME FOR YOUR SHENANIGANS! the organisation sleeper agent is trying to distract me with basic maths, i am resisting as best i can, but may need an assist, el psy congroo.
>>8402281
I remember that thread.
>>8402385
wait
hah hah
>>8401043
>x=++x;
This could work depending on the language. It's just a really retarded way of doing it.
Not an equation, but the notation for a progress.
A concept regarding infinity, if there has to be a "solution".
>>8400585
Literally the only correct one
>>8401885
same answer
the answer depends on how you define 1. /thread
>>8403222
It does, the same way my whole sentence depends on how I define "It", "does", "the", "same" and so on. Fuck off you retard. The set of solutions is the empty set.
>>8400563
shorter to type x++
>>8400563
The trivial ring is the only ring satisfying such an equation for some x.
If you want something that's not a ring, look at the extended real numbers or something. If indeed you define \infty + 1=\infty.
>>8400763
what are we suppose to do?
>d/dx(x) = d/dx(x+1)
>1 = 1+0
>1 = 1
>>8403263
So you've proved: [math]\exists y \forall x (x+y=x+1)[/math]
Nice job!
>>8400563
Let's get serious in here boys
>>8402385
I love you...
>>8403255
>but that's not the formula in the pic
>Literally no idea what he is talking
Back to /g/ with you.
x_{n+1} = x_n + 1
>>8400563
if cs, it's x++, or x += 1
if it's math, x = 0.
>>8403394
>x = 0
You didn't think this through, did you?
>>8400563
what means solving here ?
>>8400563
You can either understand this in the context of a programming loop, or in the context of the extended reals. In the later case, the solution is [math] x = \pm \infty [/math]
>>8402792
> not enjoying the insanity of preincrementation
I had it backwards anyway
x=++x;
works.
x=x++;
doesn't
>>8403406
Not only, the equation is true for any trivial group.
>>8400763
Now THIS is the quality of shitposting that I'd expect from /sci/.
>>8400563
Only true when 1 represents the multiplicative identity. Solved.
>>8403895
go ahead and show us how that works then
|x| = 0.5
>>8403906
|x| = -0.5
x = x+1
0 = 1
Equation doesn't work, not mathematically feasible.
>>8403935
I mean, yes, but technically the answer is the empty set.
>>8404174
no it doesnt you fucking retard. it holds SPECIFICALLY for the empty set and the empty set only.
>>8404203
Let [math]R = \{0\}[/math]. Define 0+0=0, 0*0=0. Now this is the trivial ring with 0=1 (where 1 is conventionally the additive identity).
Consider arbitrary [math]x\in R[/math]. Now we must have x=0 since there are no other choices. And by definition 0+1=0+0=0. QED
>>8400563
this is simply modular arithmetic. alternatively, prime field addition.
x congruent to zero modulo n. try harder OP
>>8404217
modulo 1, excuse me.
>>8400763
I've been coming to this board for like 5 years and this is probably the best post I've ever seen.
x=x+1
X=? In The first place?
Else x = 0
Meaning x = 1 or not mathematically plausable.
x=x+1/10 wasted time
X=0 0+1 =1
>>8404216
Okay yep, you're right. I apologize, I COMPLETELY forgot about that property of the trivial ring.
Y'all niggers. x=C*sqrt(-1)
X=infinity
>>8400943
Best answer, i think
1=1+1/x
0 = 1/x
x = infinity
:^)
>>8400763
Fucking hell I'm in Probability right now and I can't stop chuckling.
>>8400563
x is transfinite and I can't be arsed to write a proof
x = x +1
x - x = x +1 - x
0 = 1
Using boolean algebra the correct answer would be x=1
>>8400563
X=1+X
X=-1+X
X=1+1+1+1+1+1....
X=-1-1-1-1-1-1-1-1.....
Infinity < X < -infinity
>>8400642
python doesn't have x++ dumbass
>>8402336
Is the 6 supposed to be a like a cylindrical nose? If so this is now my favorite ironic emote face ever
The only answer is a quantum number that simultaneously holds the value of 1 and 0.
> You too can construct a quantum number such as this one with the simple definition:
ϕ = a
ϕ = b
a =/= b
>>8400563
A math equation is a statement that has a true/false value. If the statement is true, algebra rules will get you to another equation that is also a true statement. If the original statement is false, you will end up with a final statement (the "solution") which is also false. Any other fun I can ruin for you?
>>8400563
Should be fine for any ordinal number that is not a natural number
>>8400763
fuck you nice shitpost
x=x+1
x^2=x (x+1)
x^2=x^2+x
x^2-x^2=x
x=0
>>8400563
x=/=0 since 0=1
Therefore, {x|x ∈ R, x=/=0}.
>>8400563
(x)=(x+1)
1=(x+1)/(x)
1 = 1 + 1/x
0 = 1/x
This is what you started with. x = infinity.
>>8400563
x=x+1
subtract x from both sides
=1
the answer is 1.
>>8400563
I am assuming that the elements are coming from some ring R, and that 1 is the multiplicative identity.
then
x=x+1
0=1
So we are working in the trivial ring (0), so x=0=1 for all x.
[math]x=x+1[/math]
Given
[math]\frac{x}{x} = \frac{x+1}{x}[/math]
Divide both sides by x
[math] 1=1+\frac{1}{x}[/math]
x/x = 1
[math] 0 = 1/x [/math]
subtract both sides by 1
Therefore,
[math]\lim_{x\rightarrow \infty}=0 [/math]
There is no definite outcome, however the answer can be expressed as a limit of 1/x as x approaches infinity.
>>8400763
I fucking lol'd
>>8400763
Can someone please explain this meme to me?
>>8410853
it's nonsense but -1/12 is the value of the infinite series of the natural numbers which is an epic meme
>>8410835
how do you know x isn't 0?
>>8410835
>subtract both sides by 1
subtract 1 from both sides*
are you some kind of foreigner?
>>8400763
I GET IT I GET IT
BEST JOKE EVER BECAUSE I GET IT
>>8410962
Because 0+1 =/= 0
>>8403909
That's not right If
|x|=-c, there is no solution.
>>8411146
By traditional summation, it's incorrect (and rightfully is divergent), but when plugging it into the Riemann-zeta function, you get -1/12. It's the Riemann-zeta answer that's important in physics.
>>8411175
1 = 0 in the trivial ring
>>8400563
Hmm nothing is given about what the addition operation is. So I'll just conclude that for whatever it is, 1 is the identity.
>>8400763
You are a fascinating creature.
>>8405303
I concur
>>8410024
It's simple: "=1".
Underrated post.
>>8400763
X is unaffected by change in quantity.
>>8400563
So I think everyone else is on a higher realm of thinking than me. I'm just trying to think through this by using simple algebra.
Am I solving for x?
It's false if this is the case then. x-x = 0
0 =/= 1
>>8400763
We need more people like you
Stay on 4chan for ever please
>>8412901
This is exactly right. Everyone else in this thread is not thinking on a higher level, they are just trolling. As you say, some simple algebra yields 0 = 1, which is a contradiction, which indicates that there are no values of x that satisfy the equation.
>>8412901
>higher realm of thinking
Is this what kids call all mathematics outside of grade school addition these days?
>>8412947
>0 = 1, which is a contradiction
It is only a contradiction on most sets, as noted many times in this thread (including on the 3rd post), you can have algebraic structures that have 0 = 1, so that this leads to no contradiction and leads to the solution {1} or {0} since 1 = 0.
Otherwise the solution is indeed the empty set.
let F be a field of characteristic 1. then 0=1 and for all x in F, x+1=x.
>>8410966
Are you fucking retarded?
>>8400563
x = 0 = 1 over the trivial ring
it has no solutions somewhere else homeboy
>>8410962
Because you can't divide by zero
>>8413023
>field of characteristic 1
Good job
>>8400563
I'm pretty sure 0 =/= 1
>>8414459
you're not using the right ring then
>>8400563
>>8410976
Assigning a value to a divergent series is essentially trolling.
>>8400563
x = x +1
x - x = x + 1 - x
0 = 1
>x is not real
x = x + 1
1 = (x+1)/x
x = +-inf
>>8400763
>>8414820
>assuming that 0 = 1 can't be true
you must be at least 18 to post on 4chan
>>8400563
[eqn]\mathbb{F}_1[/eqn]
>>8415032
>not understanding what is meant by "real"
You must be at least 18 to bait on 4chins.
>>8415074
>implying that that statement was explicit and not ambiguous
>>8415168
Maybe once you attain the age of 18, you will be able to interpret the meaning of statements based on context rather than complaining that everything is ambiguous.
>>8415173
you realize that the trivial ring is a real ring where 0=1 right?
>>8414619
what is this monstrosity
>>8400563
easy
x = x-1
so now
x-1 = x-1 +1 now add 1 to each side.
x = x-1
Done.
>>8415175
The trivial ring is a ring, yes. The elements of the trivial ring are not "real" in the sense of being real numbers, i.e. elements of the unique uniformly complete archimedean field.
>>8415189
Standard model langragian.
Below it is the Einstein's Field Equations.
x = infintity
x = +/- 1/2
>>8400569
x=x + 1
-x
0=1
There is no real answer.
>>8400763
this is why I love sci
Lim x ==> infinity
X = x + 1
The relationship is only true when x is equal to infinity