Differentiating from first principles?

>>8396152
g(x) = 1/1-x^2 =1 - x^2
g(x+h)-g(x) = 1- (x+h)^2 - 1 + x^2 = -2xh-h^2
[g(x+h)-g(x)]/ h = -2x - h
let h be infinitesimal
g'(x)= -2x

why the fuck is computer science lower than law and statistics, and on the same tier as fucking life science? Everyone who makes those stupid charts is retarded.

you moronic fag how fucking dare you put physics fucking engineering you inbred peace of shit

>>8396152
>philosophy in shit tier
How does it feel to be a brainlet?

>>8396229
Because CS is a joke

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289KB, 1072x1036px

>>8396152
>censoring shit

>>8396263
Why is meche only in top tier?

>>8396263
Perhaps the chartmaker was hoping to silence the bitching before it began.

>>8396270
>Computer Science
>Waste of life

Nice meme /sci/, enjoy being a labcuck.

>>8396281
But cs IS waste of life tier. It's spending 4 years of your life with spergs and other autists while others are out partying and enjoying women. And then getting your jobs stolen by rajeet.

>>8396152
insultingly retarded and outdated list

>>8396171
Assuming you mean g(x) = 1/(1-x^2) then

g(x+h)-g(x) = 1/(1-(x+h)^2) - 1/(1-x^2)
Find the common denominator

(1-x^2-1+x^2+2xh+h^2)/[(1/(1-(x+h)^2))(1/(1-x^2))]

simplify and divide by h

[g(x+h)-g(x)]/h = [h(h+2x)]/[h(1/(1-(x+h)^2))(1/(1-x^2))] = (h+2x)/[(1/(1-(x+h)^2))(1/(1-x^2))]

let h->0
lim h->0 [g(x+h)-g(x)]/h = 2x/(1-x^2)^2

We can check this by using the chain rule

d/dx 1/(1-x^2) = d/dx (1-x^2)^-1 = -1*-2x*(1-x^2)^-2 = 2x/(1-x^2)^2

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2MB, 360x270px

>>8396263
>civil and mech only top tier
Why?

>>8397080
Civil is pretty much shit tier, dunno about mech

>>8397115
>Civil is pretty much shit tier
Civil is comfy as fuck m8. if you want an easy ass job, Civil is where its at.

>>8397123
>wanting an easy ass job
>deserving of top/god tier

lmfao dude

>>8397135
enjoy grinding 60+ hours a week as any other kind of engineer.

>>8397140
imo engineering as a whole should be in top tier at the highest. Def not god tier.