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is this legit? or is the 2 not supposed to be taken out like that?

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Thread replies: 19
Thread images: 4

File: gif.latex.gif (1KB, 79x83px) Image search: [Google]
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is this legit? or is the 2 not supposed to be taken out like that?
>>
yes its 'legit'
>>
File: CodeCogsEqn.gif (823B, 64x139px) Image search: [Google]
CodeCogsEqn.gif
823B, 64x139px
>>8392433
even this?
>>
Three steps to do something that only needs one, lol American...........
>>
You can't take it because of the exponent rules since it's in the parenthesis. He only got the right answer by luck.

b^8(2b^4) = c

log(c) = log(b^8(2b^4))

by properties of logs

log(c) = log(b^8) + log(2) + log(b^4)

By the commutativity of logarithms axiom

log(c) = log(b^8) + log(b^4) + log(2)

= log(b^8 * b^4) + log(2)

= log(b^12) + log(2)

= 12 log(b) + log(2)

Raise everything to e

exp[log(c)) = exp[12log(b)] * exp[log(2)]

c = b^12 * 2 = b^12 + b^12

= 2(b^12)
>>
>>8392432
No you have to use the product rule

[math] b^8(2b^4)=b^8(2)+b^8(b^4)[/math]
>>
>>8392440
How's elementary school treating you OP?
>>
>>8392432
sorry it's actually (2b)^4 not (2b^4). does that mean i can still do this?
>>
>>8392446
>>
>>8392454

Now it's different. Exponents distribute over multiplied terms just like multiplication would over additive terms. (2b)^4 = 2^4 * b^4

So it would not be a 2 you can move out of the parenthesis, it would be a 16.
>>
File: CodeCogsEqn.gif (982B, 94x62px) Image search: [Google]
CodeCogsEqn.gif
982B, 94x62px
>>8392457
like this?
>>
>>8392457
also if i wanted to to move e^x to the left and right is it the same as any other fundamental where it's just (x+-c)? like e^(x+-c) to do horizontal translation and then reflection is just e^-x and -e^x with respect to the x/y axis?
>>
>>8392463

go to desmos and graph it faggot

and watch what happens
>>
>>8392466
ok so it was. thanks.

if you have a exponential function Cb^x and you know two points, is m just C in this case? and if so, if i sub it in, which i got as 9 and then use another point, say (1,6), can i then solve for b?

basically can i just go 6=9b^1 ergo 6/9 is b?
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>>8392440
2^8 =/= (4^8)/2

2^8 = 4^4
>>
>>8392449 you are retarded

see>>8392475
>>
>>8392459
Yes just like that
>>
>>8392446
Or just use Law of Exponents, add and add the superscripts of the b variables together to achieve 2b^12.
>>
>>8392432
depends on what you are multiplicating and how you wish to define multiplication.
Thread posts: 19
Thread images: 4


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