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>mfw there are people on sci RIGHT NOW who don't know calculus

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Thread replies: 75
Thread images: 9

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>mfw there are people on sci RIGHT NOW who don't know calculus
>>
it's not knowing that's hard. it's doing the excersises so you can recall menial shit like cos'(x^2)= cos(x^2) * (2x)

or what the trig identities are. along with their inverses.

like am i supposed to know that cos(x)=sqrt(sin(x)-1 by heart?
>>
>>8389842

>like am i supposed to know that cos(x)=sqrt(sin(x)-1 by heart?


Why is that so hard to remember? You can remember the quadratic formula, can't you? This is even simpler.
>>
>>
>>8389821
I'm in algabra 2 trig, and in college.
I never gave a fuck about math until it hit me that if i major in anything but a stem feild i might as well not bother with college, so now I'm trying to catch up hard.
>>
>>8389846
You took the bait, friend.
>>
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>>8389821
mfw
>>
>>8389846
i don't use the quadratic formula i just put my equation to zero and solve for x.
>>
>>8389821

>bothering to know calculus when you can just numerical differentiation it all away

Come back when you learn how to program.
>>
>>8389842
>cos'(x^2)= cos(x^2) * (2x)
It's actually cos'(x^2)= -sin(x^2) * (2x) brainlet
>>
>>8390103
fuck off i only just recalled this.
>>
>>8389981
0 = 44x^2 - 321x + 52034
Solve this without using the quadratic formula or using technology
>>
>>8390110
You can solve literally any quadratic just by completing the square
>>
sup
>>
>>8390110
0 = 44x^2 - 321x + 52034
-52034= 44x^2 - 321x
[sqrt(-52034)]/44=x^2-321/44x
sqrt([sqrt(-52034)]/44)=x - -321/44 sqrt(x)
sqrt([sqrt(-52034)]/44)=x + 321/44 sqrt(x)

x=0 in this.
>>
>>8389842
all you have to remember is the pythagorean theorem and the definition of a derivitive. everything else can be easily derived (^_^) from that.
>>
>>8390135
what's the pythagorean theorem again?
>>
>>8389842
>it's hard to remember simple rules for derivatives

Good job you triggered me.
>>
>>8390136
It's not trig that's hard it's having to recall menial shit like the relationship of the hypotenuse of a right triangle to the length of its sides.
>>
>>8390136
sin a / A = sin b / B = sin c / C
>>
>>8389842
> cos(x)=sqrt(sin(x)-1 )
>implying cos(x) is never negative

w e w e w e w e w
>>
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>>8390131
>x=0
>0 = 44(0)^2 - 321(0) +52034
>0 = 0 - 0 + 52034
>0 = 52034

Bruh
>>
>>8390142

cant tell if bait but that's the law of sines
>>
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>>8390141
>>
>>8389981
I just use iteration lol
>>
>tfw you know how to derive stuff that you don't memorize
>feelsgoodman.jpg
>>
>>8390233
are you fucking stupid? all that proves is that there's no solution at x=0
>>
>>8390135
>conflating the two meanings of the word 'derived'
reported, I hope you get perma'd
>>
>>8389842
remembering basic things is hard I understand.

brainlets just can't compete.
>>
>>8391635
shut the fuck up if you call me a brainlet one more time i will literally make the slope of your forehead approach zero using the Leadpipe function's derivative L'(t).
>>
>>8389842
Nice bait. But I'll still need to mention that the entire [math]\cos{x} = \sqrt{1 - \sin{x}}[/math] crap is all derived from swapping stuff around in [math]\sin^2 x + \cos^2 x = 1[/math]
>>
lol what a joke. Your average person should understand probability and statistics -- those are much more important on a daily basis.

Calculus is honestly just a pedagogical artifact that people like OP enjoy braging about. That doesn't mean its not useful. It is. It's just not a big deal if you don't know it if you on average won't need it.
>>
>>8391643
keep telling yourself that brainlet.
>>
>>8389842
Holy shit you by far win the award for stupidest post on 4chan ever.
First of all cos'(x^2)= -2xsin(x^2).
Secondly cosx= sqrt(1-sin^2x).
The fact that 10 people have responded to you and no one's called you out on your stupidity shows that /sci/ is full of brainlets who can't do hs level math
>>
>>8389856
I took college algebra after a 10 year break, and it was definitely helpful in helping me remember and sharpen my algebra skills, especially since I had a garbage precalc after.
>>
>>8389856

Triggered
>>
>>8389842
That's a strong b8.
>>
>>8389846
>You can remember the quadratic formula
ha ha, nope, but I can derive it
>>
>there are people without 4chan passes on this board
>>
>>8391966
this is a classless board, remove yourself scum
>>
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>tfw good at calculus but struggling with linear algebra
What's a good resource that will help me develop intuition for this wizardry?

I just can't into all these hyperplanes and equations of lines in 3d space and spanning subspaces and shit.
>>
>>8391977
>linear algebra
>y=ax+b
>hard
>>
>>8391966
>there are people on 4chan right now who think there is content worth paying for on boards.4chan.org/.
>>
>>8392003
weak b8
>>
>>8391977
Youre using a wrong book if geometric perspectives of linear algebra arent shown
>>
>>8392041
>I was only pretending to bait
>: v
>>
>>8391977
My book didn't really give very good intuition for what was going on either. Use 3blue1brown's videos on YouTube for help visualizing.
>>
>>8391623
Which is exactly what he was trying to show...
>>
I'm in calc 1 right now.

I don't think I understand stuff very well but I have an A, mostly because homework + tests are online.

I'll be taking a proctored midterm soon which i'll probably fail if I'm not allowed any sort of notes.

I think it's pretty dumb if they require me to memorize the one million formulas for shit.
>>
>>8391635

there are people who score Calculus because they remember, but understand nothing. so fuck off with your memory meme, a computer is smarter than you if all you do is memorize.
>>
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>>8389821
>post on /sci/ hoping to discuss math and science
>remember that half this board is high-schoolers and undergrads arguing about majors and pop-sci memes
>>
>>8392047

>learning math
>using visuals instead of actual logic
>can't into R^n > 3

is /math/ doomed?
>>
i don't even know algebra lol

fight me
>>
>>8390110
FU, I'll derive the quadratic formula - then use it.

[math] \displaystyle
\\ ax^2 + bx +c = 0 \; \; \; \; \; \; | \; \cdot 4a \\
4a^2x^2 + 4abx + 4ac = 0 \\
4a^2x^2 + 4abx = -4ac \; \; \; \; \; \; | \; +b^2 \\
4a^2x^2 + 4abx +b^2 = b^2 -4ac \\
(2ax + b)^2 = b^2 -4ac \\
2ax + b = \pm \sqrt{b^2 - 4ac} \\
2ax = -b \pm \sqrt{b^2 - 4ac} \\
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
[/math]
>>
>>8389846
>>8391642
>>8391774
i want you to leave
>>
>>8392905
(You)
>>
>>8391643
Kys yourself
>>
>>8393218
dafuq is thsi witchcraft
>>
>>8389821
I never learned it because in my school nobody taught it
>>
>>8393361
I want you to go to sleep early so you can pay attention at school and actually learn some maths kiddo
>>
>>8393522
>>8393218
Here's a stupider but more intuitive derivation

ax^2+bx+c=0
= (xsqrt(a)+b/(2sqrt(a)))^2 = -c+b^2/4a
xsqrt(a)+b/2sqrt(a) = +-sqrt(b^2/4a-c)
xsqrt(a) = -b/2sqrt(a)+-sqrt(b^2/4a-c)
x = -b/2a +-sqrt(b^2/4a^2-c/a)
x = -b/2a+-sqrt(b^2-4ac)/sqrt(4a^2)
x = [-b+-sqrt(b^2-4ac)]/2a
>>
>>8390584

When you can't find any way to do it iteration is pretty much the best way. Just keep on converging onto that true value until the number of decimal places correct surpasses the place the test tells you to round to.
>>
>>8389856
I took "college" algebra in 10th grade. Some people I know that are taking "college" algebra in college have taken other classes like trig or pre calc. It's basically a scam to sucker students into another useless gen ed class.
>>
Calculus is easy. Its the algebra that gets ya
>>
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>>8389821
>mfw there are people passed the age of 16 allowed to live not knowing calculus
>>
>>8389821
Is every reply in this thread b8 or are people really this retarded?
>>
>>8390136
h^2 = a^2 + b^2
>>
>>8394445
> gives no math statement
> acts as if has any authority

>>>/x/
>>
>>8389842
sin x = (e^pi*i - e^-pi*i)/2i
cos x = (e^pi*i + e^-pi*i)/2

this is all you need to know
>>
>>8394345
Holy crap, that first step, isn't intuitive to me.
Lots of moving parts.
[math] \displaystyle
ax^2+bx+c=0 \\
\displaystyle
\left ( \sqrt{a}x+ \frac{b}{2 \sqrt{a}} \right )^2 = -c + \frac{b^2}{4a}
[/math]
>>
>>8394511
It's completing the square
Here's one that's even more intuitive

ax^2+bx+c=0
x^2+bx/a=-c/a (this is allowed because a!=0)
(x+b/2a)^2=-c/a+b^2/4a^2 = (b^2-4ac)/4a^2
x+b/2a= +-sqrt[(b^2-4ac)/4a^2] = +-sqrt(b^2-4ac)/2a

x = [-b+-sqrt(b^2-4ac)]/2a
>>
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>>8389821
Nice bait op but you realize this is an 18+ site, right?
>>
I learnt it, got a grade for it and then forgot it.
>>
>>8389821
Calculus is useless anyways lol
>>
>>8389842
[math]e^x = \cos(x)+i \sin(x)[/math]
Thread posts: 75
Thread images: 9


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