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turn math into money

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assume that you are gambling/investing whatever you want to call it

everytime you do it, you have a 51% or higher chance of succeeding. does this mean you will inevitably (>99%) make a net profit over a sufficient number of times?
what function do you use to figure this out?
>>
>>8341334
No. It's possible that you would lose every game for all time
>>
>>8341334
What you are describing is literally called the gambler's fallacy
>>
>>8341334
Your story doesn't give us any idea of what the EV is. How much are you losing when you lose and how much are you winning when you win?
>>
That's what a casino is numbskull
>>
>>8341398
No it's not you fucking retard.

>>8341339
Jesus fuck he asked a precise question, if you have no answer just shut the fuck up, kids.

>>8341334
OP what you are looking for is called the binomial distribution, check it out.
>>
>>8341334
You won't turn mathematics into money if you lack the basics.
>>
>>8341495
>he asked a precise question

No he didn't. He said you have a 51% chance of success, but didn't say how much your win compares to your loss. Maybe you get $1 if you win, but lose $1000000 if you lose.
>>
>>8341590
No retard. In either case you'll use binomial distributions.
>>
>>8341591
>look at me guys I just took an introductory stats class

It's an unanswerable question given the information OP provided. All you'd be able to solve is the amount of wins to losses in a finite amount of attempts.
>>
>>8341748
mhhhhh if only there was a way to express solutions non numerically for a general case...
What is it with stats that makes retard go "HURR DURR YOU CAN'T NO NUTHIN"
>>
>>8341334
Not necessarily. What if you have enough losses in a row that you go broke, and can't bet anymore?
>>
>>8341334
Yes, as long as the original investment returns a profit of more than 48/51 times what you invest when it succeeds, you can form a strategy which guarantees you a 99% of a net profit. This is because expected value is the same no matter how you invest:

0.51p-0.49 = 0.99x-0.01
x = (51p-48)/99 > 0
p > 48/51
>>
>>8341334
>>8341854
Oh, and of course you can have a strategy which gives you a 100% chance of net profit as long as the original investment has a positive expected value.
>>
>>8341761
you can't answer OP's question definitively, so you need more information
>>8341334
>does this mean you will inevitably (>99%) make a net profit over a sufficient number of times?
>>
>>8341912
>you can't answer OP's question definitively
Yes you can. Let's say the profit from a successful investment is p times the amount invested. Using a simple martingale betting system, you can keep raising your investment to cover your losses until the investment succeeds. The number of investments you need to make to have a 99% chance of getting a successful investment, and thus a net profit, is n such that 0.49^n = 0.01. So you only need to make 7 such investments and you will have a more than 99% chance of having a profit. Of course, the expected value from the investment will not change, because you have a very small chance of the investment failing all 7 times and you losing a lot more money than that potential profit.
Thread posts: 16
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