this

Posting your math homework on a Deep South Cajun Cookout forum

>>8323343
Just propegate the integral throughought the function, dumbass.

>>8323355
uh... what?
propagate+integral in google doesn't lead to very many informative results

try justifying each step and you'll see where you fucked up

>>8323343
I can't imagine what this function looks like, nevermind applying the algebra

>>8323343
>a^2 - x^2
try trig substitution

>>8323371
>conversion to a form easier to work with
>u-substitution
>reverse chain rule
>power rule
uh, what am i looking for?

>>8323387
thats what the online calculators are saying to do, im just wondering if thats the best way.

>>8323343
You have to prove this. You could just take the derivative of the right hand side instead.

>>8323398
Oh I see now that's exactly what you did, lol

>>8323343
Are those 2's or a's? God your handwriting makes me wanna throw up

>>8323366
Propegate not propagate dummy. Propegate the integral through the function.
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Jk that guys a retard

>>8323343
To prove this, you can just differentiate the right hand side. If you want to know how to integrate the left hand side, all you need is a trig substitution: x = a*sin(u). This will let you simplify the integral down to (1/a)^2 integral sec^2(u) du. Clearly, the derivative of tan(u) is sec^2(u), so we get [(1/a)^2]*tan(u) + C. But we need to get back in terms of x, so x/a = sin(u), which gives us [x/a]/sqrt(1-(x/a)^2) = tan(u), hence, [(1/a)^2]*x/sqrt(a^2 - x^2) + C is the answer.

>>8323343
Check your integrating step, it's wrong. You can do that if it was an x, but not if it an x^2.