TEST [tex]asdf[/tex]

[latex]\frac{1}{2}[\latex]

>>8295866
[math]\Latex[/math]

[math]\frac{1}{2}[/math]

\simeq{A}{B}

[math]\simeq{A}{B}[/math]

[math]B\simeq \barA[/math]

[math] $\overbar{\mathbb{Z}}$ [/math]

>>8295880
[math] \bar{\mathbb{Z}} [/math]

>>8295881
[math] A \therefore K \colon x \in \mathbb{X} [/math]

[math]latex{/math]

>>8295901
WTF?!

>>8295906
not as easy as it looks

>>8295905
>25-Feb-2011
>more than five years ago

[Catalog] >> /sci/guide
>> https://sites.google.com/site/scienceandmathguide/
>> /sci/ LaTeX Tutorial

for testing, try at
https://latex.codecogs.com/eqneditor/editor.php

right-click on pretty formulas
to see the code that produced it

File: sen2.png (93KB, 512x640px) Image search: [Google]

93KB, 512x640px

>>8295905
thank you

>>8295901
ah, nao I see where I fuckup
[math]latex[/math]

>>8295909
>doesn't change every fucking 5 minutes

kind of the point with latex, it's a standard

[math]\sum_{n\rightarrow 0}^{\infty} a_\rho ^\sqrt{u} + \mathbb{B}[/math]


jus tryin shit

>>8295913
five year ago, /sci/ did not use MathJax, n00b

OP here

>>8295917
I did >>8295915
from >>8295905 's info
and some intuition

>learn to learn

[math]\setlength{\unitlength}{0.8cm}
\begin{picture}(6,4)
\linethickness{0.075mm}
\multiput(0,0)(1,0){7}
{\line(0,1){4}}
\multiput(0,0)(0,1){5}
{\line(1,0){6}}
\thicklines
\put(0.5,0.5){\line(1,5){0.5}}
\put(1,3){\line(4,1){2}}
\qbezier(0.5,0.5)(1,3)(3,3.5)
\thinlines
\put(2.5,2){\line(2,-1){3}}
\put(5.5,0.5){\line(-1,5){0.5}}
\linethickness{1mm}
\qbezier(2.5,2)(5.5,0.5)(5,3)
\thinlines
\qbezier(4,2)(4,3)(3,3)
\qbezier(3,3)(2,3)(2,2)
\qbezier(2,2)(2,1)(3,1)
\qbezier(3,1)(4,1)(4,2)
\end{picture}[/math]

[math]\setlength{\unitlength}{5cm}
\begin{picture}(1,1)
\put(0,0){\line(0,1){1}}
\put(0,0){\line(1,0){1}}
\put(0,0){\line(1,1){1}}
\put(0,0){\line(1,2){.5}}
\put(0,0){\line(1,3){.3333}}
\put(0,0){\line(1,4){.25}}
\put(0,0){\line(1,5){.2}}
\put(0,0){\line(1,6){.1667}}
\put(0,0){\line(2,1){1}}
\put(0,0){\line(2,3){.6667}}
\put(0,0){\line(2,5){.4}}
\put(0,0){\line(3,1){1}}
\put(0,0){\line(3,2){1}}
\put(0,0){\line(3,4){.75}}
\put(0,0){\line(3,5){.6}}
\put(0,0){\line(4,1){1}}
\put(0,0){\line(4,3){1}}
\put(0,0){\line(4,5){.8}}
\put(0,0){\line(5,1){1}}
\put(0,0){\line(5,2){1}}
\put(0,0){\line(5,3){1}}
\put(0,0){\line(5,4){1}}
\put(0,0){\line(5,6){.8333}}
\put(0,0){\line(6,1){1}}
\put(0,0){\line(6,5){1}}
\end{picture}[/math]

File: screamingfury.gif (2MB, 593x915px) Image search: [Google]

2MB, 593x915px

WE NEED GRAPHS DAMMIT

>>8295915
put \displaystyle right after math],
it'll look better

[math] \displaystyle
\sum_{n\rightarrow 0}^{\infty} a_\rho ^\sqrt{u} + \mathbb{B}
[/math]

[math]0 \rightarrow M \rightarrow M \oplus N \rightarrow N \rightarrow 0 [/math]

>>8295989
think im gettin it
[math]\displaystyle T[\upsilon]^\beta \colon \upsilon=[x_i,y_i,z_i]
T(x_i)
T(y_i) \mapsto some matrix \begin{bmatrix}
a & b \\
c & d
\end{bmatrix}
T(z_i)
[/math]

File: 20160405_124210.jpg (805KB, 2304x1296px) Image search: [Google]

805KB, 2304x1296px

>>8296016
I'd like it more like this

>>8296019
nvm I know how now

>>8296019
[math]
\begin{bmatrix}
T(v_x)= v_i \\
\gamma \\
T(\mu) = \infty
\end{bmatrix}
[/math]

File: kjhuggfh.jpg (43KB, 480x480px) Image search: [Google]

43KB, 480x480px

>>8296027
Thank you everyone. I Know Tex now(kinda)

[math] \displaystyle
\sqrt {x^2} \ne \pm x, \quad \sqrt {x^2} = \left | x \right |
\\
|x| =
\begin{cases}
\;\;\; x & ,x \geq 0 \\
-x & ,x < 0
\end{cases}
[/math]

[math] \displaystyle
\begin{matrix}
\underline{x} & \underline{y} & \underline{x \rightarrow y} \\
1 & 1 & 1 \\
1 & 0 & 0 \\
0 & 1 & 1 \\
0 & 0 & 1
\end{matrix}
[/math]

There's a Tex equation previewer on the top left of the reply window you fucking mongs

>>8296440
[math]\displaystyle \begin{matrix}
\textbf{B} & \textbf{E}& \textbf{N}& \textbf{I}&\textbf{S} \\
\textbf{E} & \textbf{N}& \textbf{I}& \textbf{S}&\textbf{B} \\
\textbf{N} & \textbf{I}& \textbf{S}& \textbf{B}&\textbf{E} \\
\textbf{I} & \textbf{S}& \textbf{B}& \textbf{E}&\textbf{N} \\
\textbf{S} & \textbf{B}& \textbf{E}& \textbf{N}&\textbf{I} \\
\end{matrix}[/math]

[math]B^{e^{n^{i^{n^{ ^{(^{F^{r^{e^{n^{c^{h^{:^{ ^{B^{e^{n^{i^{n^{)^{,^{ ^{o^{f^{f^{i^{c^{i^{a^{l^{l^{y^{ ^{t^{h^{e^{ ^{R^{e^{p^{u^{b^{l^{i^{c^{ ^{o^{f^{ ^{B^{e^{n^{i^{n^{ ^{(^{F^{r^{e^{n^{c^{h^{ ^{R^{e^{p^{u^{b^{l^{i^{q^{u^{e^{ ^{d^{u^{ ^{B^{e^{n^{i^{n^{)^{ ^{a^{n^{d^{ ^{f^{o^{r^{m^{e^{r^{l^{y^{ ^{D^{a^{h^{o^{m^{e^{y^{,^{ ^{i^{s^{ ^{a^{ ^{c^{o^{u^{n^{t^{r^{y^{ ^{i^{n^{ ^{W^{e^{s^{t^{ ^{A^{f^{r^{i^{c^{a^{.^{ ^{I^{t^{ ^{i^{s^{ ^{b^{o^{r^{d^{e^{r^{e^{d^{ ^{b^{y^{ ^{T^{o^{g^{o^{ ^{t^{o^{ ^{t^{h^{e^{ ^{w^{e^{s^{t^{,^{ ^{N^{i^{g^{e^{r^{i^{a^{ ^{t^{o^{ ^{t^{h^{e^{ ^{e^{a^{s^{t^{,^{ ^{a^{n^{d^{ ^{B^{u^{r^{k^{i^{n^{a^{ ^{F^{a^{s^{o^{ ^{a^{n^{d^{ ^{N^{i^{g^{e^{r^{ ^{t^{o^{ ^{t^{h^{e^{ ^{n^{o^{r^{t^{h^{.^{ ^{A^{ ^{m^{a^{j^{o^{r^{i^{t^{y^{ ^{o^{f^{ ^{t^{h^{e^{ ^{p^{o^{p^{u^{l^{a^{t^{i^{o^{n^{ ^{l^{i^{v^{e^{ ^{o^{n^{ ^{i^{t^{s^{ ^{s^{m^{a^{l^{l^{ ^{s^{o^{u^{t^{h^{e^{r^{n^{ ^{c^{o^{a^{s^{t^{l^{i^{n^{e^{ ^{o^{n^{ ^{t^{h^{e^{ ^{B^{i^{g^{h^{t^{ ^{o^{f^{ ^{B^{e^{n^{i^{n^{,^{ ^{p^{a^{r^{t^{ ^{o^{f^{ ^{t^{h^{e^{ ^{G^{u^{l^{f^{ ^{o^{f^{ ^{G^{u^{i^{n^{e^{a^{ ^{i^{n^{ ^{t^{h^{e^{ ^{n^{o^{r^{t^{h^{e^{r^{n^{m^{o^{s^{t^{ ^{t^{r^{o^{p^{i^{c^{a^{l^{ ^{p^{o^{r^{t^{i^{o^{n^{ ^{o^{f^{ ^{t^{h^{e^{ ^{A^{t^{l^{a^{n^{t^{i^{c^{ ^{O^{c^{e^{a^{n^{.^{[^{7^{]^{ ^{T^{h^{e^{ ^{c^{a^{p^{i^{t^{a^{l^{ ^{o^{f^{ ^{B^{e^{n^{i^{n^{ ^{i^{s^{ ^{P^{o^{r^{t^{o^{-^{N^{o^{v^{o^{,^{ ^{b^{u^{t^{ ^{t^{h^{e^{ ^{s^{e^{a^{t^{ ^{o^{f^{ ^{g^{o^{v^{e^{r^{n^{m^{e^{n^{t^{ ^{i^{s^{ ^{i^{n^{ ^{C^{o^{t^{o^{n^{o^{u^{,^{ ^{t^{h^{e^{ ^{c^{o}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}[/math]

[math]\int_{0}^{\infty} \frac{e^x}{x}dx[/math]

>>8296038
I think your third entry is messed up. Or I haven't done any logic in a long time, because I don't remember [math]x \rightarrow y[/math] to hold if [math]x[/math] is [math]0[/math].

>>8296486
you havent done logic in a long time

x false doesnt rule out that a result holds true or doesnt.

>>8296474
[math]
{{{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}^{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}_{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}}^{{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}^{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}_{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}}}_{{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}^{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}_{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}}}}^{{{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}^{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}_{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}}^{{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}^{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}_{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}}}_{{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}^{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}_{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}}}}}_{{{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}^{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}_{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}}^{{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}^{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}_{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}}}_{{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}^{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}_{{\text{:^)}^{\text{:^)}}_{\text{:^)}}}}}}}}}
[/math]

[math] \displaystyle
\\ ax^2 + bx +c = 0 \; \; \; \; \; \; | \; \cdot 4a \\
4a^2x^2 + 4abx + 4ac = 0 \\
4a^2x^2 + 4abx = -4ac \; \; \; \; \; \; | \; +b^2 \\
4a^2x^2 + 4abx +b^2 = b^2 -4ac \\
(2ax + b)^2 = b^2 -4ac \\
2ax + b = \pm \sqrt{b^2 - 4ac} \\
2ax = -b \pm \sqrt{b^2 - 4ac} \\
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
[/math]

\frac{1}{2}

[math]\frac{1}{2}[\math]

[math] \sum_{k=0}^\infty \frac{x^k}{k!} = e^x [/math]