what do I do with the x?

>>8289684
Binomial theorem doesn't work on fractions ya dingus.

>>8289684
you factorize out sqrt(3), then only x is left in the brackets

>>8289692
haha wtf nigga. it works for all real exponents. t.netwon

(5-3x)^0.5=(5(1-0.6x))^0.5=sqrt(5)*(1+(-0.6x))^0.5.

then just use binomial theorem with X=-0.6x and n=0.5

multiply all by sqrt(5) if you want.

also -1<X<1 so -1<-0.6x<1 so -5/3<x<5/3

is this a level maths?

>>8289711
Yes I'm preparing myself for the year. I want to make something of my life so I'm paying for my course so ive been having a go at the books but I'm stuck on this problem and don't know what to do.

>>8289708
What? Isnt (5-3x)^1/2 correct though?

>>8289684
If it's (5x)^3 its just going to be 15x^3

>>8289692
>Being this wrong
Some star poster you are.

>>8289684
You're not supposed to get rid of the square root are you?

>>8289684
The 3x will be raised to each power. Examples: (-3x)^2 = 9x^2. There are no mysteries here.

I will expand these for you to see how it's done

(5-3x)^2 = 5^2 +2(5)(-3x)+(-3x)^2 = 25-30x+9x^2
(5-3x)^5 = 5^5 + 5(5)^4(-3x)+ 10 (5)^3(-3x)^2+ 10(5)^2(-3x)^3+5(5)(-3x)^4+(-3x)^5. Calculate the coefficients and the powers of x.

For fractions it's the same than for natural exponents! Just infinit expansion.

If you know how to calculate the numbers, then it's really easy. The first term doesn't have x, the second has x, the their has x^2, the fourth has x^3, etc. Just increase the powers one by one.


(5-3x)^(1/2)

First term: 5^1/2. You are done

Second term: (1/2)5^(-1/2)(-3x)/1!
The exponent of the 5 go down by 1, so you get 1/2-1 = -1/2
This gives you V5 times -3 divided by 2. 1! Is just 1
Total: -3/(2V5) x

Third term: multiply n(n-1) where n is 1/2. This gives you (1/2)(-1/2) = -1/4
The exponent of 5 go down by anither unit. You have 5^(-3/2) = 5V5
The (-3x) is to the power of 2, this gives you 9x^2
The 2! Is just 2
This gives you (-1/4)(9x^2)/(10V5)= -9/(40V5) x^2

>>8291017
That's wrong you fucking third grader

>>8291050
Care to elaborate instead of chucking insults around?

>>8291068
>>8291050
Alrghty then.

But yeah, unless I'm wrong that's your answer OP.