Pleb here. How does b divided by 1/b give you b^2.
>>8282625
/b/^2 ? pls kill me
(b)/(1/b) = b*(b/1) =b^2
>>8282625
1/x is the multiplicative inverse of x (:= inv(x))
b/(1/b) = b*1/(1/b) = b* inv(1/b) = b* inv(inv(b)) = b*b =: b^2
>>8282625
Solid thread
OP Thank
>>8282643
How does 1/b switch to b/1 and how do you know to multiply?
>>8282670
Dividing by a fraction is the same as multiplying by it's reciprocal.
>>8282643
only if b =/= 0
THIS IS /SCI/?
HAHAHAHAHHAHAHAHAHAHAH
MORE LIKE DUMB FAGGOTS THE BOARD
>>8282625
It takes b times 1/b to make a whole and b times a whole to make b, so (1/b)XbXb = (1/b)b^2 = b. Therefore b^2=b/(1/b)
>>8283892
thank you for your example,
Captain Capslock
>>8282625
Division by b is the multiplication of the multiplicative inverse, which is defined as a number "a" such that ab=ba=1.
What is the multiplicative inverse of 1/b then? Well by the same notion it must be b since 1/b*b=b*1/b=1. So 1/(1/b)=b.
>>8284151
fuck off you fucking dumb community college RETARD
DUMB CUNTS!!!!!!!!!!!!!!!!!!!!1
>>8284216
BTW I MAJOR IN PURE MATH
b = 0
1/b = infinity
0/infinity = 0^2
>>8282625
Two real numbers whose product is 1 are called reciprocals. Therefore, a/b and b/a
are reciprocals because a/b*b/a = ab/ab = 1. For example, 2/3⋅ 3/2 = 6/6 = 1.
Because their product is 1, 2/3 and 3/2 are reciprocals. See pic next.