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Math Riddle

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I´ve got a Math Riddle to solve which left me clueless. I ask for your help to solve it, because I didn´t find anything on a similiar Riddle.

The Riddle goes as following:

After a Project, 4 individual corporations get a sum x, corp 1: a half of the sum minus 2000, corp 2: a third of the sum minus 5000, corp 3: a quarter of the sum plus 1000 and corp 4: 2000.

Its about Money / Euros and its defined that corp 4 only gets 2000 and the other get those Values.

The Question is: What is the overall sum?
>>
>>8268736
How is your algebra homework a riddle?
>>
>>8268756
Doesn't matter; it's not even solvable.
>>
>>8268736
5.55555555555555555555555555555555555...
>>
>>8268736

x is the total sum. a,b,c, and d are the respective corporations.

x=a+b+c+d

a=(x/2)-2000
b=(x/3)-5000
c=(x/4)+1000
d=2000

x=((x/2)-2000)+((x/3)-5000)+((x/4)+1000)+2000

Try it now.
>>
>>8268844
I'm proud someone told this pleb about the substitution method in systems of equations. Thank you.
>>
Impossible to solve x could be literally anything and having Corp 4 as a defined amount doesn't help since there is no relation to x
The best answer that can be given is in the form X +/- integer
>>
>>8268756
Definitly not my Algebra Homework, but a riddle in a Magazine for electricians.
>>8268844
Thanks for the answer. To clarify, it was one of my solutions, kinda different approach (without a calculator) but now Im sure thats the correct answer.
>>8268851
Thanks for the helpful reply...
>>
>>8268736
x/2 - 2000 + x/3 - 5000 + x/4 + 1000 + 2000 = x
x/2 + x/3 + x/4 - 4000 = x
5x/6 + x/4 - 4000 = x
26x/24 - 4000 = x
26x/24 - 96000/24 = x
26x - 96000 = 24x
2x - 96000 = 0
2x = 96000
x = 48000

Literally high school algebra. What is going on here?
>>
>>8268929
Wanted to make sure, as I had different answers based on different approaches. Me, a 4th grader cant solve high school math.
>>
>>8268934
>I had different answers

You mean different numbers for solutions or different procedures.

Anyways, let me tell you that the guy who assigned a variable for each company is a fucking retard. Literally the most useless 'oh look at me I know linear algebra' way to solve this problem.

YOU HAVE ONE VARIABLE.

Also, this is not even a riddle.
>>
>>8268939
Different numbers as Solutions and 2 different procedures. Yes, guy who made it is a retard.
Call it whatever you want, doesn´t matter, got my answer. So Case Closed.

Hell, even I am a retard.
>>
>>8268934
You know you have to be 18 or older to be on this site?
>>
>>8268955
I am over 18 and in 4th grade.
>>
Well you see OP you have to go to the sticky and read up on the math section and get all the books in the textbook recommendations section. Lets hop to it and get that basic mathematics textbook open. We aint got time to play around with this 4th grade shit you gotta start proving stuff ASAP
>>
>>8268966
and i am a unicorn
>>
>>8269272
I'm a banjo.
Thread posts: 17
Thread images: 1


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