Well, smart alecs - which is it?

16/2

>>8263365
Neither, it's 4√2

>>8263365
2V(2) * 4 V(2) is exactly the same as V(2)*V(2)*4*2 = 16

divide by 2 and you have 8

>>8263365
You can factorize on top

2(root2*2root2)/2
= root2*2*root2
commutativity
= root2*root2*2
Algebraic definition of root2, given that real numbers don't exist.
= 2*2
=4

>>8263416
>factorize a product
>[math]a^2xy=ax\cdot ay=a(xy)=axy[/math]
Bait or retarded

>>8263421
>Bait or retarded

Let me give you a hint

>given that real numbers don't exist

>>8263365

What the fuck? There's not even any ambiguity in this one. It's 8

>>8263365
[eqn] \frac { 2 \sqrt { 2 } \times 4 \sqrt { 2 } } {2 } = 4 \left ( \sqrt { 2 } \right )^2 = 8 [/eqn]

>>8263365
We can't do cross product between scalars.

File: 1455231381099.jpg (20KB, 320x452px) Image search: [Google]

20KB, 320x452px

>>8263365
Depends on what the value of x is.

File: image.jpg (685KB, 2120x1964px) Image search: [Google]

685KB, 2120x1964px

>>8263365
8

>>8263456
Who the fuck says we can't? Just make scalar analogue for the Levi-Civita symbol. Easy.

>>8263371
/thread

>>8263365
[math]\frac{2\sqrt{2*4\sqrt{2}}}{2}=2\sqrt{2\sqrt{2}}[/math]

:^)

>>8263365

2*sqrt(2)*x*4*sqrt(2)=8

x = 1/2

or 2*sqrt(2)*x*4*sqrt(2)=4

x = 1/4