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can sci predict how this sequence continues? i cant figure it

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Thread replies: 15
Thread images: 2

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can sci predict how this sequence continues?
i cant figure it out and could realy use some help

>0
>1
>01
>10
>000
>001
>011
>110
>111
>0010
>0100
>0101
>0111
>1010
>1101
>1110
>00001
>...
>>
-1/12
>>
>>8261826
Next is 0, the sequence is periodic
>>
>>8261851
i know for a fact that it is not periodic
>>
>>8261855
I know for a fact that you are a faggot.
Then it's 00001, the sequence is constant afterwards.
>>
>>8261856
geez, you didnt have to come to this thread.
what is wrong with you
>>
It's 17

From the rule that the next number in any finite sequence is always 17

This works for any finite sequence
>>
>>8261859
What is wrong with YOU? The solutions are correct, if you don't bother posting a proper formulation of your problem don't complain about people picking the most obvious answers
>>
/sci/ is retarded
>>
>>8261826
Binary numbers?
>>
File: 1463011996511.png (186KB, 463x515px) Image search: [Google]
1463011996511.png
186KB, 463x515px
>>8261826
Does the size of the registers containing the bits actually increase? This sequence is not simply about the bits themselves, but also about the number of bits in the registers?

Is this the whole question?
>inb4 just taking some notes here below

1. You have a 1 bit register twice (2/2). You use all the combinations. (0,1)
2. A 2 bit register twice (2/4). You use half the combinations. (1,2) (The middle ones.
3. A 3 bit register 5 times (5/8). (0,1,3,6,7)
4. A 4 bit register 7 times (7/16). (2,4,5,7,10,13,14)

5. So how many times will you use your 5 bit register out of the 32 possible combinations?

Or are the number supposed to all run together?
Hmm

What is actual question being asked?
>>
>>8262148
the actual question is a bit tricky to explain.
the 1's and 0's are mappings where 00001 means 0(0(0(0(1))))

the sequence contains these mappings as elements.

the register containing the bits should always increase.
its not only about the bits but also about howmany bits in the register.
its in ascending order non repeating and is known to be an infinite sequence
>>
>>8262148
from
>00001
it continues like

>00011
>00100
>00111
>01001
>01100
>10000
>10010
>10011
>10101
>10110
>11000
>11111
>000001
>>
>>8262423
>>8262148
allowing for 13 registers with 5 digits.
>>
>>8262122
not in the traditional sense. but i suppose it doesnt matter allot.
they are not random which you can verify at your own convenience.
Thread posts: 15
Thread images: 2


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