im confused, if the rate of heat flow between two systems is:

[math]u_t = -\Delta u[/math]
set all constants equal to 1 nigger

>>8249549
> using \Delta for the Laplacian

>>8249549
im not a nigger im a chef please explain to me what that means

That's the wrong equation for two different materials.
This is the right one.
P=\frac { -A∆T }{ \sum { \frac { { x }_{ i } }{ { k }_{ i } } } }

>>8249551
>not using [math]\Delta[/math] for Laplacian
spotted the physicist

tell me which operator looks better, [math]e^{t \Delta}[/math] or [math]e^{t \nabla^2}[/math]? notation-wise it's a no-brainer

>>8249559
[latex]P=\frac { -A∆T }{ \sum { \frac { { x }_{ i } }{ { k }_{ i } } } }[\latex]

>>8249559
[math]P=\frac { -A∆T }{ \sum { \frac { { x }_{ i } }{ { k }_{ i } } } }[\math]

>>8249566
[math]P=\frac { -A∆T }{ \sum { \frac { { x }_{ i } }{ { k }_{ i } } } }[/math]

>>8249568
so you essentially average out the materials conductivity?

this would mean that ignoring convection and heat capacity water would defrost something quicker than air at the same temperature?

>>8249559
[math]-A\Delta t \div \sum \frac{x_i}{k_i}[/math]

>>8249573
Yes
[math]{k}_{{H}_{2}O}=0.58
{k}_{Air}=0.024[/math]

[math] QT=P2T [\math]