10 dollary doos says you fuckwits can't solve this 1st year

frame of referance?

>>8247575
whatever makes it easiest to solve

>>8247576
That's dumb
0 with respect to A

>>8247570
>itt anon tries to bait people into doing his homework for him.

Nice try, but it's been done before.

seems to me it's also v0
otherwise the wheel would kinda disintegrate wouldnt it

>>8247589
>Tries to come up with excuses as to why he can't solve it
nice try faget, keep studying arts/philosphy

>>8247595
Will do, enjoy failing out of university.

>>8247590
yeah it's also v0 (if that vector also points to the left)
you could also decompose it in sin and cos because the v0=tan(velocity at A) so...

>>8247570
[math] \omega = \frac{v_{0}}{r} [\math] ,

where [math]r[/math] is the radius of the wheel.

>>8247603
fuuck

>>8247601
sorry I meant to say (velocity at A) times tan(theta)
but im not sure

>>8247590
Wrong.

Op do your own hw.

>>8247603
Oh nevermind, it's meant to be a cycloid. Parametrically describe it and then get your velocity magnitude.

Ill give you a hint, use
Va=Rw*i^ +Rw(-sin(theta)i^ +cos(theta)j^)

>>8247570
it translates with v0 but also rotates around O.
Therefore its vectorial velocity is

v_A = v0 + w*r*(sin(theta), cos(theta)) = v0 + v0*(sin(theta), cos(theta))

frame of reference is the system in which the wheel has the constant velocity V0.

>>8247581
>reference frame
>accelerating
back to high school for you

[math]\bar{v}=V_0( (-\ sin (\theta)-1) \hat{e}_x +\cos {\theta} \hat{e}_y )[/math]