Math- Summation

>>8202969
It's saying that the sum of 1/k from 1 to n is roughly ln(n) to zeroth order.

>>8202974

zeroth order?

>>8202979
n^0.
O(1).
A constant term.

>>8202979
That's the error estimation, I mean.

File: error.jpg (19KB, 700x525px) Image search: [Google]

19KB, 700x525px

>>8202987
Just whipped this up in matlab for you. Here's the error for the first 1000 values of n.

>>8202985
in what retarded field is this notation used

>>8203021
Computer science

in my notes, I show
[math]\displaystyle \sum_{n=1}^{m} \frac{1}{n} \approx \ln \frac{2n+1}{3}+1[/math]

What the fuck is wrong with you people

https://en.wikipedia.org/wiki/Euler%E2%80%93Mascheroni_constant

\displaystyle \sum_{n=1}^{m} \frac{1}{n} \approx \ln \frac{2m+1}{3}+1

[math]\displaystyle \sum_{n=1}^{m} \frac{1}{n} \approx \ln \frac{2m+1}{3}+1[/math]

>>8203266
this is useless unless you describe its precision. the fact they tend towards each other is trivially just op

>>8203035
>O(1) = C
lmao

>>8202969
it means that you are unable to read your textbook

[math]3x + 2y = 8[/math

[math]3x + 2y = 8[/math]

File: swM0MRE_.jpg (12KB, 240x240px) Image search: [Google]

12KB, 240x240px

>>8204569
Holy Monkey Balls!

>>8202969
the o(1) is actually +-1 in this case