Thread replies: 11
Thread images: 2
Thread images: 2
Anonymous
mathematica tips and tricks 2016-05-11 14:36:10 Post No. 8066262
[Report] Image search: [Google]
mathematica tips and tricks 2016-05-11 14:36:10 Post No. 8066262
[Report] Image search: [Google]
File: mathematica.jpg (20KB, 480x360px) Image search:
[Google]
20KB, 480x360px
I have 2 matrix from 2 different grayscaled Imagedata.
i merged in a single matrix qq and now i must apply a formula that was sent to me today as ColorFunction.
ColorFunction -> (RGBColor[1 - 1/3 #[Alpha], 1 - #[Alpha], 1 - #[Alpha]] /. [Alpha] -> 0.9 &)
i never used this option and when i try using it i get only errors, i tried with
ColorConvert[Image[qq],ColorFunction -> (RGBColor[1 - 1/3 #[Alpha], 1 - #[Alpha], 1 - #[Alpha]] /. [Alpha] -> 0.9 &)]
i am just a novice in mathematica
how should i solve this problem?
>>
>>8066262
Try
ColorConvert[Image[qq], ColorFunction -> (RGBColor[1 - 1/3 # 0.9, 1 - # 0.9, 1 - # 0.9])&]
>>
>>8066274
ColorConvert::imgcstype: ColorFunction->RGBColor[1-Power[<<2>>] #1 0.9,1-#1 0.9,1-#1 0.9]& is an invalid color space specification.
nope just errors
>>
>>8066284
Well then there's something wrong with the output the color function is producing.
Do you know what it's supposed to do? Do you have examples?
>>
Actually did you even read the documentation for ColorConvert?
https://reference.wolfram.com/language/ref/ColorConvert.html
I don't think it's supposed to take a ColorFunction
>>
>>8066297
then what command has this function since it change the color?
>>
>>8066293
like background of pic related
>>
>>8066311
Just map your function over the pixels.
>>
>>8066330
how the fuck do i do it?
>>
File: Capture.png (32KB, 709x668px) Image search:
[Google]
32KB, 709x668px
>>8066333
Like this
Replace f with your whatever color function you are trying to use, and use the correct numbers for the partitioning
>>
>>8066344
thanks
Thread posts: 11
Thread images: 2
Thread images: 2