JUST

>>8062440
Is that supposed to be difficult?

>>8062447
for kids like OP, yeah

F = kx
Fc = (mv^2)/r

Wow 2 equations op so hard

>>8062440
well you know the radius of a circle is pir^2. so you have the circumference now. the squiggly w looks like roughly 45 degrees so thats just an eigth of the area. now to find the area of the sin wave you just take the integral from m to the radius. whats so hard?

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>>8062563
>the squiggly w looks like 45 degrees

>>8062440
r''(t) = -k/m*(r(t)-R) + w^2 / r(t)

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>>8062563
>radius of a circle is pir^2

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>>8062563
>squiggly w

You bring shame to this board

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>>8062567
>>8062652
>>8062667

>> Falling for that bait

>>8062567
lol yo shutup

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>>8062710
>le epin bate
Take it to /r9k/

Just post the circumference

>>8062563
>squiggly w

[eqn]L=\frac{M}{2}(r\dot{\theta})^2 - kr^2/2 [/eqn]
solv'd

>>8062830
assuming its vertically oriented too
[eqn]L=\frac{M}{2}(r\dot{\theta})^2 - kr^2/2 - Mgr\sin\theta[/eqn]

Given M,k,w find R

>>8063378
>what is the equilibrium length

>>8062830
Question
When a term has a dot over it, what does that signify? I kept seeing it in my differential geometry class, but the professor never told us what it was.

>>8063378
for real

mRw^2 = 0.5kR^2

thus, R=(2m*w^2/k)

>>8063430
en.wikipedia.org/wiki/Time_derivative

>>8063451
Thank you friend.

>>8063450
Check dimensions: MRw^2 is a force while kR^2/2 is an energy.

>>8063414
You need a minimum radius r (unstretched spring or mass offset from center)
Mw^2R = k(R-r) -> R(k-Mw^2) = kr -> R = r/(1-Mw^2/k)

>>>/b/683646934

get headache from this stupidy