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Why math...

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Thread replies: 11
Thread images: 2

File: WTF-Math_001.png (18KB, 794x567px) Image search: [Google]
WTF-Math_001.png
18KB, 794x567px
Pic explains
>>
>>7988532
It's not as complicated as you think it is. Watch a khan academy video or something.
>>
>can't do basic algebra
>am i too dumb for math
No, you lack practice.
>>
>>7988532
what do you want know?
>>
>>7988811
>what do you want know?
THIS

Evaluating the original equation, I get X = 6Y-24
There are an infinite number of correct answers.
Is this a troll? If so, it's more confusing than anything.
>>
File: Screenshot_20160408-232748.png (106KB, 1440x2560px) Image search: [Google]
Screenshot_20160408-232748.png
106KB, 1440x2560px
You're supposed to find where they intersect
>>
>>7988905
It's a single function. Notice there is an x on one side and a y on the other. It's not a system of equations.
>>
>>7988761

The only right answer
>>
>>7988532
You have an equation with two variables.
At best, you can develop a relationship between the two variables. As in "when one changes, the other changes. Here is the rule that shows how it changes."

But there is no single answer, because a relationship represents an infinity of answers.
>>
>>7988532
http://www.davdata.nl/math/axbyc.html
You should know this by your third semester.
>>
>>7988532
Linear diophantine equations either have 0 or infinite solutions.
If [math]\text{ax}+\text{by}=c[/math], [math]a,b,c\in \mathbb{Z}[/math], and [math]\frac{c}{\gcd (a,b)}\in \mathbb{Z}[/math], you can find [math]x=x_0[/math] and [math]y=y_0[/math] solutions through the Euclidean algorithm, and all other real solutions can then be given as [math]x=x_0+\frac{b}{\gcd (a,b)}*t[/math] and [math]y=y_0-\frac{a}{\gcd (a,b)}*t[/math] where [math]t\in \mathbb{R}[/math]
Thread posts: 11
Thread images: 2


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