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If i^i has a numerical value, why the fuck doesnt i?

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Thread replies: 16
Thread images: 2

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If i^i has a numerical value, why the fuck doesnt i?
>>
yo yo yo hol up
if u stop smocking your fucking weed
u would know that imaginary numbers be bullshit bro
>>
>>7971112
it's the square root of -1
>>
>>7971112
Use Euler's Formula
>>
>>7971115
yeah but the square root is when you big the two, and if you big two negatives they become minuses
how tf can them numbers go minus one?? im telling ya man, you probably smoked a full leaf just now, fuck
>>
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79KB, 798x770px
>>7971112
because i is not i^i you fucking idiotic undergrad
>>
>>7971134
>implying someone is an idiot for not knowing the properties of complex powers of complex numbers
>>
>>7971112
i does have a numerical value. Take a look see:
i^i=.2078
(i^i)^2=.2078^2=.0432
i^(i^2)=.0432
i^(-1)=.0432
1/i=.0432
i=23.14
>>
>>7971188
But 23.14^23.14 =/= .2078
>>
>>7971188
Oye! ^ isn't associative!
>>
>>7971112
If i^2 has a numerical value, why the fuck doesn't i?
>>
>>7971244
[math]i[/math] is just an imaginary number we use for muh -1 memes. There exists no real number that is a solution to [math]\sqrt{-1}[/math]
>>
>>7971251
>There exists no real number that is a solution to sqrt(-1)

Well duh
>>
>>7971112
If -1 * -1 has a positive value, why doesn't -1?
>>
>>7971545
>If 1 >= 0, then why isn't -1?
>>
>>7971121
>yeah but the square root is when you big the two
I don't know why big the two is so funny
Thread posts: 16
Thread images: 2


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