Taking Calc 2 over the summer

Why? Cal 2 is not as tough as everyone around you makes it out to be. Its the series that's tough.

Just make sure you know all of the common identities for derivatives and integrals. Also, review your trig and trig identities, that's a big part of calc 2.

>>7953120
don't review calc 1, review trig and polynomial expansion.

>>7953142
>Don't review calc 1

two thirds of calc 2 is just advanced calc 1.

>>7953139
I have to study, I took calc 1 in the fall...

>>7953120
Pick up a textbook and do some problems. Watch some YouTube or khan academy videos.

>>7953120


Just know your trig. Nothing in Cal II is hard. The only derivatives you're gonna see in there are when using u-subs, other than that every other problem you're gonna get is an integral.

If you want a nice easy text to help you out use "Thomas Calculus Early Transcendentals 12th Edition" and find the solutions manual.

Also, don't not learn anything because "oh I'll never seen it again" the only thing you don't need is disk/shell method. You absolutely need to know how to do everything else.

www.17calculus.com

You're welcome

>>7953120
calculus 2 is literally computation

just do 10 exercise a day for your free A

>>7953288
>Actually studying in easy maths

>>7953142
>>7953150

That guy's right though. A lot of Calc 2 are just derivatives, integrals, and infinite series using trig identities

be careful with integration by parts. i had a test on it today and got donkey kicked in the head

>>7953304
Maybe you just aren't cut out for it

>>7953288
>just do 10 exercise a day for your free A
Per topic or overall?

>>7953288
Where do I get a lot problem sets? Is there any good website available?
I'm studying in germany. We rarely use books as course reference here.

>>7953346
>>7953287
Can you just not read or something?

>>7953120
f'(x) < 0 means f is ____
f'(x) > 0 means f is ____

f''(x) < 0 means f is ____
f''(x) > 0 means f is ____

Be able to draw up examples of each with polynomials, sin, cos, e, and log. You'll do fine.