0^0=1 prove me wrong

also

0/0 = 1

>>7936417
0^n=1
n=1
0^1 != n

qed

>>7936430
>winrar

>>7936425
how many times can you organize 0 into groups of 0? 1

>>7936425
0/0 = 1 is correct.
But also 0/0 = 2, 0/0 = pi, 0/0 = llama.
Why?
Let x = 0/0.
Then 0x = 0.
Any x solves this equation.
See https://en.wikipedia.org/wiki/Indeterminate_form

>>7936417
Combinatorially and set-theoretically, yes.

As the form of a limit, it is indeterminate.

>>7936430
Think back to when you learnt x^0 = 1, you learnt a ting

Sir/Maam, you are about to learn tings :)

0/0 is not a defined number.
0^0, likewise, is not a defined number.

Because its not defined, we could call it anything, 1 included, but no more or less than any other value

*However* suppose you have some function which tends to an undefined representation and we want to evaluate this function, what do??

This, sir/Maam: https://www.youtube.com/watch?v=PdSzruR5OeE

Also, 0^0 is the limit as x approaches 0 of x^x

>>7936867
I did not realise it was set-theoretically valuid, can you elaborate on this?

>>7936425
x/0=0

>>7936441
Ahh this answers the set theoretical question I see

>>7936933
>>7936417
See here OP

>>7936925
I meant to refference OPs post, my bad

0 is not a number.

>>7936965
Came here to say this. However, 0^0 could =1 if you think about it in a meta sort of way.

0 times 0 = 1 set of nothing

>>7936930
the number [math]0^0[/math] represents the number of functions from a set of cardinality [math]0[/math] to a set of cardinality [math]0[/math].

That is, the number of functions from the empty set to the empty set. There is exactly one such function: the empty function

>>7936965
Depends what you mean by number

>>7936965
In quite a few sets of 'number', 0 is an entry

>>7936417
>0^0=1 prove me wrong
Can't prove you wrong, because this is in fact true.