Mäth thrädd

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>>7920643
I'll stay.
>I still remember my trigonometric identities

Excuse me? This is a Science & Math board, not a Useless Math Exercises board.

>>7920713
>not integrating by parts
>being this much of a faggot

>>7920713
I did not expect this desu. +1

>>7920787
Show your solution please.

Anyone know where I can get an emulator for the Casio fx-82au calculator?

Need one pretty bad right now.

>>7920814
I'll let you hijack the thread.
AFAIK, every Casio FX emulator I've seen costs money. I've never seen one for the model you're searching for either.

>>7920643
STUPID GORILLA POSTER BTFO

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>>7920826
This is just the beginning.

>>7920643
>Covering Kurisu with gorilla meme

No anon, you should leave.

>>7920713
>>7920787
Why not just multiply cosec(x) by [cosec(x)+cot(x)]/[cosec(x)+cot(x)]?
The answer of ln|cosec(x)+cot(x)| + C trivially pops out from there.
Much better than that convoluted mess or integrating by parts.

>>7920938
That's the more intuitive answer.

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>>7920643
MATH THRAD

Lol, who even uses csc outside of the US? During my time in high school and college csc and sec were mentioned once.

>>7920643
Sup with the monkey? Is it some kind of homework mascot?

>>7921318
Weeaboos are a burden on society.

You're all doing this wrong, it's obviously

[math]\frac{c^2 \cdot s \cdot x^2}{2}[/math]

>>7920938
Because that's the most obvious option

use t = tan(x/2)

You will get as solution: Ln(tan(x/2)) which is the correct solution

>>7921870
forgot +C

>>7922388
yep.
[eqn]\int^x \csc(t) dt
= \int^\frac{x}{2} 2 \csc(2 t) dt
= \int^\frac{x}{2} \csc(t) \sec(t) dt
= \int^\frac{x}{2} \frac{ \sec(t)^2 }{ \tan(t) } dt
= \int^{ \tan(\frac{x}{2}) } \frac{1}{t} dt
= \log \left| \tan \left( \frac{x}{2} \right) \right| + C
[/eqn]
Pretty much the same method can be used for [math]\int \sec(x) dx[/math] or something like [math]\int \frac{dx}{\sin(x)+2}[/math] which was in a thread here a while back.
Also testing how /sci/tex handles longer lines.

ln|2sin x| + pi/2 + ix + C