Where is my fault?

>>7717906
You're using your notebook sideways, and you're also using graph paper.

What the fuck man? The better question is what you've done right, if anything at all

>>7717906
Why would the integration constant need to be an element of the reals?

>>7717917
>graph paper
Literally nothing wrong with that, what does a /sci/entist use?

>>7717926
Just a snarky response while I looked at your problem.

Why did you put the i in the integrand with the cosine when it's cos + i(sin)

>>7717931
nevermind, you didn't.
it's +i(integrand)

i'm just retarded ignore me

>>7717924
Any responses after this are useless. Integration constants can be any complex number.

>>7717931
I'm not even OP, but what's the most patrician-tier paper to take notes/do proofs on?

Hey, do I just wanted to integrate e^(j*phi) through 2 ways. The first one is by using the exponent law and the second is by using the formula of euler. But unfortunately both do not end in the exact same result. The first one has a real constant and the second one a complex one

>>7717934
papyrus

>>7717906
Why do you write j instead of just i

what could have been just 1 line, you had to write it into 3 lines

that's why you're wrong, because you're an idiot.

>>7717906
start with not using i

>>7717906

Why the fuck should C be real?

>>7717906
C shouldn't be real, the imaingary coefficient doesn't just magically go away.

I'm not sure how you got -j to be 1/j, maybe it's a property I've forgotten.

Otherwise it seems you've done everything correctly

>>7717934
I like thick printer paper (say 100 g/m2)
It's nice to be able to manage your line spacing/margins however you want

>>7717906
Breh what kind of notebook is that, brand and square per inch

>>7717906
>06▶>>7717917 >>7717924 >>7717964 >>7718114 >>7718148 >>7718199 >>7718219
>Does somebody know where i've done something wrong?
How did you condense the complex number into a single constant in the reals? Shouldn't it be some constant in the complex?

>>7718199
He's right because:

[math]\frac{1}{j}\cdot \frac{j}{j} = \frac{j}{-1} = {-j}[/math]

>>7717906
the I only gets multiplied with the intergrand not the constant.

>>7718212
Can you get any good notebooks with just printer paper?

>>7718302
sketchbooks

>>7717906
Assuming that the constant of integration for a complex integral is real in step 1