is it multiplied of divided 2ac in the quadratic formula?

>>7682248
2ac is part of the discriminant.

2ac is still alive

>>7682248
neither
>>7682252
4ac* (the discriminant is b^2-4ac)

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>>7682252
trolled hard

>>7682271
>4ac* (the discriminant is b^2-4ac)
4ac = 2(2ac)

So yeah 2ac is part of the discriminant.

>>7682280
2a = 2ac / c so it's part of the denominator though

>>7682290
Yeah I guess.

>>7682291
It's also part of the numerator, friend.
Because b= (b+2ac) -2 * a * c

>>7682290
>Daily reminder wavelength is part of the equation for gravitational force, lambda/lambda hehehehe

>>7682248
Dumb goatposter

>>7682345
dumb dumb goatposter poster

>>7682255
Still 2015

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>>7683034

>>7682248

Google it.

b +/- sqrt((b^2)-4ac)(2a)

>>7682248
>actually using the quadratic formula and not just completing the square
ishygddt

>>7682290
It's actually part of the quadratic equation overall
Because:
x=(-b +/- ((b^(2ac/ac)-2(2ac))^( ac/2ac)))/(2ac/c)