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Hey /sci/, got a n00b math/signals question: If I have a simple

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Hey /sci/, got a n00b math/signals question:

If I have a simple signal sin(x), I can convert a sample taken at some point (x,y) on that signal to a complex number by using Euler's formula. e.g. the point (pi/2, 1) on the sine curve becomes complex number 0 + 1i on the unit circle in the complex plane.

What if the signal is not a simple sin(x), but is some arbitrary non-periodic signal? How do you convert an (x,y) sample into a complex number?
>>
>>7638652
Pretty sure about this, but not completely. With your notation, a point (a, b) would become
b * e ^ a*i
= b (cos(a) + i * sin(a))
so in your example,
(pi/2, 1) => 1 * e ^ (pi * i / 2)
= cos(pi/2) + i * sin(pi/2)
= i
= 0 + 1i
for a general function f, its representation at a point x is given from applying the above formula to (x, f(x)).
(x, f(x))->f(x) * e ^ x * i
= f(x)(cos(x) + i * sin(x))
>>
>>7638665

thx. what's the reasoning for multiplying by b (or by f(x) in the last example)?
>>
>>7638685
That's the part that was making me not completely sure. It's a system consistent with the example you gave, but I'm not sure it's correct.
I'm thinking that f(x) will be the magnitude of the complex vector and x will be the vector's angle.
>>
>>7638694
>>7638685
Same poster. So in your example, the vector has magnitude 1 and angle pi/2, which clearly corresponds to 0 + 1i or just i.
>>
>>7638697

yes. because i used sin(x) and that maps to a unit circle. but if an arbitrary function does not map to a unit circle, should the magnitude be sqrt(cos(a)^2+sin(a)^2) ?
>>
>>7638713
That always yields 1, so probably not.
When you take the magnitude to be f(x), you gain a bijection between ]0,2*pi[XR and the complex numbers.
>>
>>7638863

> ]0,2*pi[XR

can you please explain what this means
>>
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everything i read in signal processing books is talking about sin(2*pi*f*t + phi(t) ) idealized signals. i am trying to understand how samples of real signals (e.g. radio) are converted into complex numbers.
>>
>>7638898
The Cartesian product of the open interval with lower bound zero and upper bound 2*pi and the real numbers, or the set of all pairs with a first element in ]0,2*pi[ and second element in the real numbers, R.
I should actually replace R with R+, the set of all strictly positive real numbers. Sorry.

Basically, for every x and y such that 0<x<2*pi and y>0, there is a unique value associated to (x,y) in the complex numbers. Namely, y*(cos(x) + i * sin(x)).

This is becoming more related to analysis or set theory though, so it may not be so useful.
>>
>>7638910

i see
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