A car is driving at a constant speed when the driver applies the brakes, giving the car a deceleration of 3.50m/s^2. The car comes to a stop at a distance of 34.0m. What was the car's speed when it travelled 17.0m from the point where the brakes were applied?
1. 10.9m/s
2. 14,5m/s
3. 10,7m/s
4. 21,0m/s
5. 15.3m/s
How do I get the answer?
>>5636268
I'M THE TODDLER
>>5636268
Fug I can't remember physics lessons at all
Use Kinematic equations for the x direction. Since u have a constant velocity
I dunno, I'm bad at physics :(
The equation for this would be "v_final^2 = v_initial^2 + 2*a*d". I forget how you derive this, but it follows from the others IIRC, so just consider it known a priori. Anyway, you need to use this twice: once with a final v of 0 and a distance of 34 to figure out your starting velocity, and then use that as the initial velocity with a distance of 17.
>>5636268
Just remeber that acceleration is a second derivative of speed! That d = v*t + 0.5*a*t^2!
It's 1. 10.9m/s
v0 is 15.43m/s.
>>5636403
... I love you