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your literally retarded if you can't answer this

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Thread replies: 17
Thread images: 4

File: 1491511187984.jpg (19KB, 367x255px) Image search: [Google]
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your literally retarded if you can't answer this
>>
what about my literally retarded?
>>
>>5342308
all i see is boss baby.. lol
>>
>>5342308
the answer is 13 potatoes

Your fortune: Good Luck
>>
It's 130 with extra dip, cheese, and some soda
>>
The answer is

yes
>>
>>5342384
? That would give

-1 + -1 + (0/0) = 4.

I agree that there are an infinite number of solutions, though. The whole thing appears to be a homogeneous cubic in three variables, so the set of solutions in R^3 or C^3 should have some very interesting properties. I'm not sure what they are, though. (I think it might even be a surface at most places.)
>>
That would give

-1 + -1 + (0/0) = 4.

I agree that there are a nice number of solutions, though. The nice thing appears to be a nice cubic in nice variables, so the set of nice in R^3 or C^3 should have some very nice properties. I'm not nice what they are, though. (I think it might even be a nice at most places.)
>>
File: burypinkgirl.png (1MB, 5000x4859px) Image search: [Google]
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>>5342403
>>
>>5342352
no it's purple
>>
File: whoa.gif (140KB, 226x262px) Image search: [Google]
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>>5342420
>>
>>5342308
Math is 4 chumps
>>
One equation three unknowns, not solvable for specific values.
>>
my literally retarded?
>>5342700
dubs, nice
>>
>>5342700
Sure, but there's no requirement that your solution is unique; any values that work are enough to satisfy the question. Since you have too many variables, you can just set some of them to whatever you want. For example, if you set apple = 0, pineapple = 1, you get a degree 2 polynomial in banana (you can't set both to 0, unfortunately, but the set of illegal values has measure zero, so most random choices will work). That gives apple = 0, banana = 2+ sqrt(3), pineapple = 1.
>>
>>5342736
>>>/qa/
>>
here is my answer :^]
Thread posts: 17
Thread images: 4


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