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Give me a number and I'll try to make a complicated equation to find that number
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27
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69
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Twe-twe-twentysixteen
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>>5171531
1 = x^(i^2(e^log(1))) * ((3↑↑2)/3)^1/2 * 3^ln(e+e^m) , m=(infinity",n=1)Σ[2^-n]
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58008
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>>5171563
what le fug is ↑↑
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>>5171622
nice dubs
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Knuth's up-arrow notation ? dum stupid cia niggafication
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>>5171556
(7((10^(2!-1)+e^(iπ/2)+e^(iπ/2))/4)^2)x + 3! * x - x^2 = 0
n = |x|
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>>5171649
its complicated
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>>5171657
yep
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Idk if I'm 100% correct on these, but does it matter anyways?
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Here's a good number
https://m.youtube.com/watch?v=Ue1LS2eGc1g
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>>5171622
log(-e^(iπ))[d/dx[5x^3+7!/3*x^2+x+ln(e^"oenty-one")]]
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eleventy-one
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>>5171528
Square root of -9
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>>5172007
3^(e^(iπ)) = ln(e^(iπ))/π * x + d/dx[e^(ix)] + sin(x) - i*cos(x)
Thread posts: 20
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Thread images: 1