It's literally 2016 and you still can't solve this.

File: Dragon Ball Super - 048 - HOPE!! Again - Awaken in the Present, Trunks [DragonTeam][F1AF644C].mkv_snapshot_09.10_[2016.07.01_00.08.12].jpg (174KB, 1280x720px) Image search: [Google]

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>>4680460
Not as hard as pic related

>>4680460
0=26

Unsolvable, I told you this 9 years ago.

>>4680461
50 r-right?

>>4680461
550?

>>4680461
It's 50 you fucking retard.

>>4680461
Easy. 50

>>4680460
unsolvable
>>4680461
550

>>4680461
550

>>4680460
-26
>>4680461
550

feels good to have superior american education

>>4680463
>>4680465
>>4680466
>subtracts before multiplying
this is why we establish rules
so we can all get the same answers
because math means fuck-all unless we can all agree on certain rules

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>>4680463
>>4680465
>>4680466

>>4680465
Order of operations you retard. Multiplication is first, then subtraction.

>>4680469
>-26
What did he mean by this?

>>4680466
>>4680465
>>4680463
You dumb shits.

>>4680469
>-26-7=19+-26
What.

>>4680469

>-26
>burger education

>>4680473
If you do the math you get 0 = -26 which is just nonsense.

>>4680461
Is using a ÷ symbol a clapistan thing? I literally never seen this used in real life.

>>4680460
-12

>>4680469
Did you just subtract x from x and get -x? Because that's not how fucking subtraction works.

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>>4680469
>-26
Please tell me you're pretending to be retarded.

>>4680470
No fuck you there is only one way to do math and it is fucking left to right.
Why the fuck would you jump around going HURR MULTIPLY HERE DIVID HERE AND THEN go back and do the other shit and that's not including exponents
NO LEFT
TO
RIGHT
GO FUCK YOU AND YOUR PEMDAS STUPID SHIT

What the fuck happened here?
Please, someone burn this thread to the fucking ground.

x=±infinity
how does it feel that anime outwit you?

>>4680476
Amerifag here and I don't know WHAT the fuck this guy did

>>4680460
>x - x = 26
woah

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>this thread again

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>>4680482
What. Please don't go into STEM.

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>>4680461
Well obviously that's 500.45

>>4680460

x equals infinity or negative infinity

>>4680461

Don't make me waste my brain power trying to solve your order of operations riddle just write the problem in the right order sensei

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>>4680473
>>4680475
>>4680476
>>4680480
>>4680481
nice try you idiots, i even showed my work for full credit

>>4680460
X-7=19+x
-Xx=25
X=5

>>4680492
>steps 2/3
>x-x=-x
Nigger, I literally understood what you did before you even showed me. Now read >>4680480 again.

>>4680492
For some reason you dividing by one instead of just dropping it actually got me more than X - X = -X.

>>4680461
Order of operations

1000-450=550

>>4680492
The x's cancel out you dumbfuck. x - x = 0

>>4680488
But this is wrong. At some immeasurably large number, a digit changes.

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>>4680492
WHAT THE FUCK?

>>4680488

>x=0.33333

wrong, x ≈ 0.33333....=/= 1/3

>>145563067
>Children are taught that / is the same as the division sign. So they don't know to treat it as a fraction
What. How does that change the answer?

It's unsolvable.

>>145563112
You're getting meme'd on, son.

>>145563067
They should learn how to insert formulas in their powerpoints.

It could be taken as:

(20/5) (2*2)
or
20 / (5 (2*2) )

And those two are different equations that will bring different answers.

>>145563112
20/5(2*2)

20/5(4)

20/20

= 1

>>4680461
Trick question. You can't have a - and x sign in the same math problem.

>>4680460
No Solution

>>4680461
550

>>145562924
16

Easy Peasy

>>4680504
>powerpoints

presentations/visual aids I mean

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Jesus christ, this is literally middle achool shit. Are all americans this retarded? Fucking capitalists.

>>145563112

multiplication > division > plus > minus

the answer is 1. That "new way" is some dumb shit invented in the burger school system so niggers dont feel like niggers. Because anyways if someone thinks is 16, he clearly wont get a university degree anyways.

>>4680488
Limits

>>4680506
wat

>>145563112
The confusing part is whether the (2*2) is on top or on the bottom of the vinculum.

Can we skip any further PEMDAS shitposting and get straight to the ones with the math that makes me want to crawl in a corner and cry for attempting to STEM on them?

>>4680492
this doesn't look even the slightest bit like it came from a breathing conscious human

In step three did you divide -26 by -x and get... -26?
And after that you divided 1x by 1 to get 1x???
And step two literally states 0 = 26

what the FUCK is going on here

>>4680510
>multiplication > division > plus > minus
No.

>>4680509
Not all of us burgers are this dumb.

>>4680510
Wrong when using order of operations multiplication and division are equal and are given priority set from left to right rather than multiplication coming before division

Correct answer is 16

>>4680462
>>4680467
>>4680477
>>145562896

All these plebs saying OP's pic is unsolvable. https://en.wikipedia.org/wiki/Quotient_ring

Assuming we're dealing with the quotient ring Z/26Z then the answer is simply "True" because it's equivalent to x=x.

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>>4680505
>>4680510
Welp. Time to end myself.

>>4680509
Americans are asleep right now. most of the people posting in this thread are yuropeans and aussies

>>4680510
Are you fucked in the head?
Multiplication = division, and addition = subtraction

>>4680510
No, it's
Parantheses > division/multiplication > plus/minus
With left to right as a general rule as well, meaning that you start with the leftmost parentheses.

>>4680501
>>4680505
>>4680510
>>4680518
>>4680520


20
--------------- vs 20 ÷ 5 * (2 * 2)
5 * (2 * 2)


20
---- 20 ÷ 5 * 4
5*4

20
---- 4 * 4
20


1 16

>>4680510
>Because anyways if someone thinks is 16, he clearly wont get a university degree anyways.
I have an engineering degree and it's 16. It's 1 if you write it like this 20/(5(2*2)).

>>145562924
20 / 5 * (2*2) = 20 / 5 * 4
= 4 * 4
= 16

>>145563067
No, that's literally PEMDAS
If you interpret it as a fraction, you multiply the denominator by (2 * 2) and get 20 over 20 which simplifies to 1

Or you simplify 20 over 5 firsthand and then multiply by (2 * 2)

This is also identical to arguing whether or not to multiply or divide first with PEMDAS

>>4680525
>"applied mathematics" classes
Well, that explains it.
Pack it up, guys.

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>>4680500
>what is long division
Fucking idiot.

>>4680524
That's not about it being a fraction or not, nigger, that's about which numbers are part of the denominator. It being a fraction or a division operation changes literally nothing because they are the same.

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>>4680497
>x's cancel out
>draw a snowflake or multiplication symbol
do you even know what you're saying

>>4680510
Depends. If there is a minus sign already in the equation division takes priority over multiplication.

>>4680519
Train a kid to say that and see what the Common Core does about it.

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>>4680532
What?

>>4680484
the real answer

>>4680524
Fuck I forgot I have to use alt codes

20
---------------vs 20 ÷ 5 * (2 * 2)
5 * (2 * 2)


20
----20 ÷ 5 * 4
5*4

20
---- 4 * 4
20


1 16


>>4680530
Look at the math dumbass. It literally changes everything.

>>4680519
Shut up, nerd.

>>4680532
Except if there's a four in the equation and you're in Asia, then you multiply first to pass on your genes before the curse kills you.

>>4680536
>Look at the math dumbass. It literally changes everything.
"It" changes everything, but "it" is not about whether it's a fraction or division, it's literally just an order of operations ambiguity in the problem as written, which applies equally whether you treat it as a fraction or as a division operation.

>>4680536
>Fuck I forgot I have to use alt codes
Whatever you're trying to do doesn't work on /a/.

>>4680482
>murrica

>>4680531
What are you saying?

this thread is so retarded I can tell whose retarded and who isn't

>>4680542
it's you

Nice anime thread you retards.

>>4680482
>i'm going to use a system to get answers that will be different from other people
>these people beg to use the same system
>no fuck you my math is smarter than yours

I'm certain Math is not the universal language because there are at least a million retard dialects

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You should be able to solve this

>>4680543
I probably am for choosing to stay in this cesspool

>>4680544
There's already a PreCure thread.

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>>4680544
I'd rather take this than any of the generals

>>4680544
>This is the first time he ever saw this thread

>>4680546
IT TIPS TO THE LEFT DON'T LISTEN TO THE TROLLS

>math
Pointless shit. No one is going to be impressed with nerds being good with counting numbers and division like the nerdy loser that they are. Start packing up those muscles /a/ because that's what will impress people not this algebra index shit.

>>4680546
LEFT

>>4680546
because volumes are the same, the water displacement is the same, neither are exerting force on the scale, scale doesn't change

although to me it seems like these questions were written by twelve year olds or autists
or both
Actually please ask something even vaguely related to math or physics in these dumb threads for once

>>4680546
To the left. The steel ball fixed on a crane is outside the system so it won't affect anything.

>>4680546
it doesn't move

>>4680546
Left because it's connected to the beaker itself

>>4680552
>not a new ip
Decent b8

test

>>4680554
P=NP
Y/N

>>4680460
>x-7=19+x |+7
>x = 26+x
Makes no sense desu

>>4680461
>1000-900*0.5=
>1000-450=550
Wew

>>4680492
-x makes the forst x a 0, you degenerate

>>4680519
you need to find all x to solve the equation

What's heavier a ton of steel or a ton of feathers?

That's Correct

Steel is heavier than feathers

>>4680560
>Makes no sense desu
what if 0 = 26?

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Haven't seen one of these in a while.

>>4680563
https://www.youtube.com/watch?v=yuOzZ7dnPNU

>>4680565
45%

>>4680565
None, there's no more coins in my pocket.

>>4680563
>>4680566
There's basically no better representation of these threads.

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>>4680568

>>4680541
Whoa, hey, hey, don't lump that idiot in with us. I thought his left-to-right retardation was some Eurofag shit.

>>4680546
Right

>>4680564
How is that real if our eyes aren't real?

>>4680568
You're flipping the same coin every time, anon.

>>4680574
ORZ

The instruction wasn't clear if I would return the coin to the pocket after tossing it or not so I assumed that it won't be returned.

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>>4680492
1 - 1 = 0
2 - 2 = 0
3 - 3 = 0
x - x = ?

>>4680565
100%, the chosen coin is the tail/tail coin.

m/a/th threads are always my favorite.

>>4680565
0.99564375605

>>4680577
I'm too tired to do math but it's something pretty close to 100% but not quite since you have to factor in the (albeit low) possibility that you just got insanely lucky with a non-rigged coin.

>>4680565
55%

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>>4680575
It's intentionally misleading.

>>4680565
55%

>>4680557
>>4680555
Neither does the ping-pong ball. You might be tempted to say that because it's filled with air and would float in water that it would pull the left beaker it's attached to upward, but the beaker is what holds the very water itself. The net force is zero. The only effect either ball has on the system is displacement.

>>4680461

This is BEDMAS, the answer is 550 (?) I hope?

>>4680460

I literally have no idea how to solve that question.

>>4680581
>>4680583
See >>4680574.

>>4680565
something something bayes rule

>>4680586
Yes, and? There are 20 faces with 11 tails between them.
55%

>>4680582
I havent slept in two days, too tired to try this.

If all that shit on the left = 0, isnt the answer 0 = 0

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Well?

>>4680564
That's true in Z mod 26.
>>4680582
Let z = x + y.

>>4680562
He did, cause all x solve the equation in Z/26Z.
Nowhere does it say we're working in it though.
Quotient rings are fun though.

>>4680588
I hope you aren't actually this retarded. You just got heads ten times straight with the same coin, you have new information.

>>4680585
>I literally have no idea how to solve that question.

x - 7 = 19 + x
x = 26 + x
0 = 26

>>4680593
>you got heads
>calls me retarded

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>>4680546
It tips because magic.

>>4680594
that's not a solution

>>4680546
The buoyant force of the ping pong counteracts the normal force of the beaker to the left btw

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>>4680590
I cant do this shit

>>4680546
>Same volume
Remains unchanged. Didn't know you NEETs were this stupid.

>>4680601
It can't be twice as cold as 0, just colder.

>>4680597
The answer = no solution

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Might as well.

>>4680601
Easy, 16 degrees

>>4680601
Still not as cold as the confines of my heart.

>>4680604
75%

>>4680604
50% as she has two coins.

>>4680604
50%, there are only 2 coins.

>>4680599
All you really need to solve it is the knowledge that a triangle is 180 degrees and the patience to decipher the various triangles using that knowledge.

>>4680604
2/3

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>>4680592
>Quotient rings are fun though.
Oh you like quotients huh? Show:
1. Quotient maps on topological spaces can always be written as an equivalence relation,
2. that for any homomorphism f: G -> H, the quotient G/ker(f) is isomorphic to img(f) in H, and
3. that the quotient ring R[x]/<x^2+1> is isomorphic to C.

>>4680601
We just say, that the difference between your body temperature and the one outside is hotness/coldness.
Since our body temperature is 36°, we get -36°C as result.
Ha, tricked your trick question. I win!

>>4680601
What I'm unsure about is whether or not the temperature 0 actually denotes a value of "nothing" as we understand it in the mathematical sense. Obviously, nothing times 2 is still nothing. Is the temperature 0 degrees really nothing though?

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>>4680612
>The Cox-Zucker machine

>>4680614
The thing is that we don't know which unit is used, so it is unsolvable.
If celcius or farhenheit the only way it makes sense is we have to go in kelvin and then divide by two, if kelvin, it can't be colder than 0.

>>4680612
>cox-zucker machine
goddamn

>>4680610
Total angle at Corner B = 80
Total angle at Corner A = 80
Angle at Corner C = 100

Total angle at Corner B = 80
Angle of left half part of A = 70
Angle at left of E and α = 30

Angle of left half part of A = 10
Supplement of angle at left of E and α = 30
>Angle at Corner C = 100

My brain shorted-out...

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>>4680618
>Total angle at Corner B = 80
>Total angle at Corner A = 80
>Angle at Corner C = 100

This thread never fails to amuse me.

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>>4680612
>The Cox-Zucker Machine

>>4680590
The only way to solve this I see is assuming that AB and ED are parallels, which would make alpha = 70 But they probably aren't, so i'm stuck.
to be sure I should draw that shit with actual values but I don't have what's needed.

>>4680619
Told you my brain shorted out by just trying to figure it out. Give me 10 more minutes.

>>4680590
Fairly certain there's not enough info to solve this one. Into to calculate alpha (angle AED), you'd have to know the value of the angle opposite it (BDE, or beta). But you can't calculate beta without knowing alpha. Even knowing that the intersection of BD and AE is 50/130 doesn't help.

You probably COULD use trig to figure it out, but there's no way with just elementary geometry.

>>4680482
>I failed GCSE Foundation Maths: The post

>>4680546
Left is subject to the weight of the ping-pong ball in air. Let's put it in perspective: if the ping-pong ball was filled with helium, it would actually pull the scale UPWARD since the scale has air all around it. If it's filled with air, it would only push downward by the weight of its shell.

Right is subject to a force equal to the weight of the water pushed by the iron ball. If you try pulling a rock in water with a rope, you'll notice that it's lighter (exactly lighter as the weight equivalent to its volume in water). The difference in force is applied to the water downward, and as such, to the scale.

Basically, unless the ping-pong ball is heavier than an equivalent volume of water (I.E. unless the ping pong ball would also sink like the steel ball if suspended with a string) the scale will go up to the left, and down to the right.

By the way, if you suspended a ball of steel and a ball of lead (which is heavier than steel) on both sides, each would only apply to the water a downward force equal to their volume in water, so neither side would move.

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>>4680590
Shit.

Anywhere between 1-149 is my answer.

>>4680612
Really? They couldn't have called it Zucker Cox machine?

>>4680627
I think this is designed to be unsolvable for elementary geometry.

>>4680612
Please, I'm eating breakfast.
2. I realize I can't proof algebra stuff anymore at all
3. Probably rather easy with some homomorphism.

>>4680629
Also, it is not to scale.

>>4680461
Fuck I wish I could write that neatly.

>>4680631
Textbook work is pretty much never to scale anyway.

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>>4680628
It's deliberate.

>>4680612
>Cox-zucker machine
Holy shit its real

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>tfw I'm retarded at math

Life's okay

>>4680590
75?

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>>4680634
Stronk tits

>>4680601
Since she's a scientist, I assume she means 0K, so if it's twice as cold, it can only mean this:
https://youtu.be/_SFMqBSmEmk?t=6m59s

Answer is 42. I WIN you idiots

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>>4680492
>x = 26 + x

Maybe it's because I'm absolute garbage at math but I feel like what you wrote here literally can't be an actual possibility

>>4680637
75 checks out as a valid answer when I look at it. I was focusing on BDC being 140 and AEC being 150 but that didn't lead me anywhere other than guessing and plugging in values that'd make all the triangles involved work. I don't know if either of us fucked up though.

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>>4680612
>The Cox-Zucker machine

>>4680601
16 degrees farenheit

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Who cares about math anyway.

>>4680612
>Cox-Zucker Machine
this was 100% intentional, was it?

>>4680639
Probably 0C since 0K inplies there is no particle movement happening

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>>4680645
The world, apparently.

>>4680646
A google search says that the story goes that the guy named Cox intentionally hit up the guy named Zucker just so that he could name their results Cox-Zucker, but I have no idea if it's true.

>>4680590
Are lines DE and AB parallel? Scale is off as well.

>Beliving you would ever need anything but the most basic math

Math is literally the most useless skill you can have in like 99% of situations you encounter in life.

>>4680650
Nevermind they are not.

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why do these threads always get a million fucking replies

>>4680601
0 degrees [no unit]
Best guess C/F as with K, you'd be fucking dead.

0C = 32F
0F = -17.7778C
∴16F/-35.5556C

>>4680653
>I don't like m/a/th

Fuck off

>>4680627
Using a bruteforce method by trying every angle between 1 degrees and 149 and solving every other angle and checking for appropriateness is still elementary geometry, isn't it? It does use no trigonometry.

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>>4680627
If you bisect the center triangle exactly in half using a straight line, thus creating a 90 degree angle, does the upper angle (50 degrees) not also get dividing by two, giving two right triangles, each with two angles now revealed to us, those being 25 degrees and 90 degrees, thus giving us the final angle (a) which should be 65 degrees? What makes no sense about that though is that if a = 65, then the outlines (sides D and E) will not have add up to 180 degrees because, using that same information, we can extrapolate the degree of the missing angles leading us to a line that supposedly has 175 degrees which is obviously false.

>>4680657
It's not possible without more information.

>>4680657
Nope, doesn't work. While ABE and BAD are both 80 degrees and thus bisecting BCA would create two perfect halves, the segments AE and BD don't intersect right at that bisection. AE is angled slightly more away from the AB line than BD is, meaning their intersection would be to the right of a BCA bisection, making said bisection useless.

>>4680590
>>4680637
Pretty sure this guy's right.
Call the midpoint (where AE and BD meet) F, I guess.
180-70-60 means BFA is 50, and thus EFD is 50, and BFE and DFA are both 130.
For triangle ABC, 180-60-20-70-10 (subtracting angles A and B) means C is 20.
For triangle BFE, 180-20-130 means BEA is 30, which means AEC is 150.
For triangle AFD, 180-10-130 makes ADF 40, which makes BDC 140.
For triangle EFD, 180-50 means that alpha and BDE combined are 130.
For triangle CDE, 180-20 (C) means that EDC and DEC combined are 160.
So we have the system of equations
Alpha+BDE=130
Alpha+DEC=150
BDE+EDC=140
EDC+DEC=160
Alpha=160-EDC=160-(140-BDE)=160-(140-(130-Alpha))=150-Alpha
2Alpha=150
Alpha=75

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>/a/ - Maths and Helvetica

>>4680460

>>4680492
You are a special kind of retard, aren't you?

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>>4680461
>when watching this episode thought the answer was 50
>forgot about order of operations
>tfw i had to listed have fucking shitter young Pilaf smugly explain the correct answer to me

>>4680664
>had to fucking listen to young Pilaf smugly explain the correct answer to me


Fixed.. Jesus christ not only can I not math, I cant English either apparently.

>>4680661
0%

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I forgot where I read this but here goes.

Say there are 18 sacks filled with gold coins. Each sack contains the same amount of coins as all the other sacks. However, one of these sacks contains coins that have lesser weight compared to the coins in the other sacks. How many times do you have to weight to find the sack containing lighter coins?

Pic unrelated

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>>4680658
>>4680659
Sorry. Here I thought I was being clever.

>>4680667
17 or less

>>4680667
At the very least two different sacks

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>>4680661

>>4680616
It can't be Kelvin because Kelvin doesn't use degrees.

>>4680669
>>4680670
>>4680667
I'll give the answer after at least 10 people answered.

Hint: there's only one amount so answers like "17 or less" is wrong

>it's a math thread

>>4680657
You assume that a bisection of the center angle would pass for C, but it wouldn't.

>>4680660
How did you get Alpha=160-EDC?

>>4680667
Compare sacks 1-6 and 7-12. If one pile is lighter, take those sacks, if they're the same take 13-18. Call them A-F

Compare A-B and C-D. Same logic, take the lighter pile or E-F. Call them Fry and Laurie.

Compare Fry and Laurie.

>>4680461
They're japanese so you read it from right to left. The answer is -550. What do I win?

>>4680677
=5.0x009-0001
=5x9-1
=44

>>4680667
>>4680673
I forgot some details. 17 sacks have coins that weight 10kg while the 1 sack have coins that weight 9kg.

Fuck I messed up.

>>4680679
You had one job to do.

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>tfw you struggle to solve problems Japs give to elementary schoolers

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>>4680667
>>4680679

Once

You just weigh them all and then remove each sack one by one

>>4680488
If 1/3 were 0.3333 then 1/3 + 1/3 + 1/3 would equal 0.9999. The limit to infinity however is not 0.9999. It is 1.

>>4680546
Tips right. The steel ball exerts more force on the entire system than the ping pong ball.

>>4680565
Depends on what the question is wanting.
(0.5)^11 if we're talking in a row.
0.5 because the events are independent.

>>4680582
First order ODE.
y(x) = (-3x^2 + sqrt(3) * sqrt(3 + 16x - 6x^2 - x^4) + 3)/(6x)

>>4680601
Degree is an angular measurement. We'll use metric and go with 0 however.

>>4680604
P(A|H) = P(A) * P(H|A)/P(H)
P(A) = 1/2
P(H|A) = 1
P(H) 3/4
P(H) = 2/3
Feel like I screwed up Bayes here.

>>4680590
I'll get this in a second.

>>4680661
Indeterminate. It's a paradox.

>>4680667
Once.

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>>4680681
feels bad man

>math below average

>>4680682
4

>>4680682
14

MOOOOOOOOOOOOOOOOOOOOOOOOOOODS

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FUCK YOU MOD
FUCK YOU

THIS IS A SCREENSHOT FROM AN ANIME, AND ONE OF /a/'s BEST RECURRING THREADS.
FUCK YOU.

damn /a/ threads are of such high quality they don't even get moved to /trash/

Fucking newfag mod

What a funny man

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>>4680688
Eeeeasyyy.

>>4680683
>manages to answer everything incorrect
Amazing.

>>4680695
Don't feed the dryhard shit eater with the IQ of 40.

>>4680488
x = 1/3
x = 0.333...
x = x
1/3 = 0.333...
3(1/3) = 3(0.333...)
3/3 = 0.999...
1 = 0.999...

So what?

If x = mod and fag = x

Mod = ?

>>4680705
x

>>4680660
Your solution is wrong, and the system
Alpha+BDE=130
Alpha+DEC=150
BDE+EDC=140
EDC+DEC=160
Has infinite solutions, and I can prove it:
Alpha=70
BDE=60
EDC=80
DEC=80
solves it perfectly, but so does
Alpha=65
BDE=65
EDC=75
DEC=85
And
Alpha=75
BDE=55
DEC=75
EDC=85
or
Alpha = 1
BDE=129
EDC=11
DEC=149
Basically, all this system does is tell us stuff we already knew (EDC is 10 degrees more than Alpha and DEC is 20 degrees more than BD).
So this approach can't reach a conclusive solution, and the problem can't be solved with geometry alone. QED.

>>4680488
I don't understand the question, there's just some very basic math in there.

Fuck it I'll rewrite the riddle.

Say there are 12 pouches. Each pouch contains 20 gold coins and every coin in those pouches weight 10kg with the exception of one pouch containing coins that weight 9kg. You are provided with a scale that can only measure one pouch at a time (stop being a smartass). How many times do you have to use the weight in order to find which pouch has the 9kg coins?

And no you can't measure with your hands or other tools. Just the scale.

Also provide your reasoning. No random number.

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>>4680712
I don't think it's a question. It's just showing that 1 is 0.9 repeater.

There.

>>4680715
Empty all the pouches and make piles out of the coins. Fill one pouch with 1 coin from each the first 3 piles, 2 coins each from piles 4-6, and 3 coins each from piles 7-9.
If it weighs 179kg, the lighter coins are in pouch 1-3, place 1-2-3 coins from each and compare:
if it weighs 59, it's pile 1 that has the lighter coins.
If it weights 58, it's pile 2
If it weighs 57, it's pile 3
If it weights 178, it's pile 4-6 and you do the same as above
If it weights 177, it's pile 7-9 and you do the same as above
If it weights 180, it's pile 10-12 and you know the drill.
So I say it's exactly twice, as I see no way to solve it with only one weighing.

>>4680466
>>4680477
>>4680488
>>4680499
>>4680500
>>4680511
>>4680522
>>4680533
>>4680544
>>4680555
>>4680566
>>4680577
>>4680588
>>4680599
>>4680600
>>4680611
>>4680622
>>4680633
>>4680644
>>4680655
>>4680666
>>4680677
>>4680688
>>4680700
Checked.

Your fortune: Reply hazy, try again

>>4680590
>>4680683
20 degrees is the angle. Too much bisection hurts.

>>4680715
Label them from 1 to 12. From each numbered pouch take an amount of coins equal to the number. You will have 78 coins. This would be 780 kg, but one pouch is lighter.
780 kg - whatever weight you get = what bag it is. You weigh once.

>>4680688
Make an 8 from the 2.

>>4680712
They're just giving the proof in a really shitty way.
x = 0.999...
10x = 9.999...

10x = 9.999...
1x = 0.999...
9x = 9.000...
x = 1.

>>4680721
Incidentally, since pile 9-12 can use the same method for up to 6 piles (just take 1-2-3-4-5 from the first 5 piles, and check for 150-149-148-147-146-145), this method works for up to 15 piles.

>>4680721
Nope
>>4680724
Correct! I could've sworn I read this in a manga but I forgot which one. Anyway congrats Anon!

>>4680724
But the scale can only measure one pouch at a time, it can't weigh 78 coins, only a pouch containing 20.

>>4680730
No, the problem clearly states you can weigh only ONE POUCH at a time and not to be a smartass. If it could weigh 780 kgs of coins, it could take at least 3 pouches, which contradicts the premise.

x = 0.99999 ... 99
10x = 9.9999 ... 90

10x - x = 8.9999 ... 91
9x = 8.9999 ... 91

x = (8.9999 ... 91) / 9
x != 1

Q.E.D.M.F. (Q.E.D. Mother Fuckers)

>>4680715
>How many times do you have to use
Ask someone to weigh each sack for you.
You used the scale 0 times.

>>4680484
feels like infinity is not a number and theres only a few situation where it can be used like one. this is not one of those situations

>>4680488
but this is just true tho. like theres nothing wrong with this math.

you can also show this by saying that since the sum of an infinite geometric series with rate R is 1/(1-R). since 0.9999... is equal to the sum of 9*1/10*(1/10)^n for n from 0 to inf, the infinite sum is 9*1/10*1/(1-1/10)=(9/10)/(9/10)=1

>>4680737
>>4680724
>>4680700
>>4680717
>>4680488

It's just how decimal representation works. In the usual mathematical construction you're forbidding an infinite sequence of 9s from a point on so that the representation is unique. Otherwise 0.9999...= 1 by construction, it's the same number.

>>4680460
heh that's a trick question OP x is NOT anumber thereFORE! it can't be added
I win gimme my prize

divide the 18 coins into three piles of 6 coins each.
weighing 1: put one of these piles on each side of the scale, leaving the remaining pile aside. if the piles on the scale are of equal weight, the pile set aside contains the lighter coin. if one pile on the scale is lighter than the other, that pile contains the lighter coin. in either case you have identified which pile of the three contains the lighter coin, and you will use that pile for the next weighing.
weighing 2: take the pile of 6 coins you identified in weighing 1 as the lightest pile and divide it into 3 piles of 2 coins each. then repeat the process of weighing 1 with each of the three piles of two coins replacing each of the piles of six. after this, you will have identified a pile of two which contains the lighter coin.
weighing 3: clear the scale and place each of the coins of the pile of two you found in the last weighing on its own side of the scale. you will have found the lightest coin in 3 weighings. this is both the minimum and maximum using this method, as well as for a method containing 27 coins (weigh 2 groups of 9 with one set aside, then two groups of 3 with one set aside, then 2 groups of 1 with one set aside)
of course there are methods with smaller minima- for example, if you pick two coins at random and weigh them, you might get lucky and identify the lighter coin in fewer than three tries, but it could take you many more than that.

>>4680510
2-1 = 2+(-1)
????????

>>4680492
X-X =0

>>4680460
Unsolvable, solution is 0=26
>>4680461
550 due to pemdas

>>4680694
kek mega underr8d

>>4681111
quads confirm
HEY EVERYONE GIVE THIS >>4680694
POST A LOT OF (you)s

>>4680601
-35.5 degrees celsius.

>>4681305
Lolol for a minute I thought you said - 35.5 degrees CALCULUS roflmao XDXDXDXD

>>4680469
>American Education
>Superior
cool cool

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if it takes 5 machines 5 minutes to produce 5 cogs, how many minutes does it take for 100 machines to make 100 cogs

Your fortune: Excellent Luck

>>4681467
5 minutes

>>4680563
Neither because a ton of steel and a ton of feathers both weigh one ton?

>>4680460
-7 = 19
easy

>>4680460
subttact 6 from each side. you get x-13=x+13. so x=+/-13.

so it is sqrt(sqr(13)).

or in laymans terms, square 13 then take the square root.

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>>4680460
Impossible

>>4680461
550

>>4680488
true

>>4680510
multiplication and division are done before addition and multiplication, they are not on separate layers. This is because division is just multiplication represented differently and subtraction is just addition represented differently.

>>4680546
I've seen good videos on this one but can never remember how to do it

>>4680565
how many ways are there to make 10 tails with the unfair coins? 2^10 = 1024
how many ways are there to make 10 tails with fair coins? 1
how many outcomes are there? 1024*10 = 10240
it helps here to visualize every possible scenario as a giant tree:
there are 10 starting paths, 9 of which are fair coins, 1 of which is unfair
we have 10240 total ending paths
in 9 of the ending paths we have paths which started as fair coins, and made it out as all tails
in 1024 of the ending paths we have coins which started as unfair and ended up as all tails
all the rest of the paths ended with at least one head in them
now, since we know OUR path ended with 10 tails, there are only 1024 + 9 = 1033 total paths that it COULD have been
1024 of these of course are unfair coins
therefore there is a 1024/1033 = 99.1287512% chance that you picked the only tails coin
if this doesn't make sense to you, try doing the same approach but with much less coins, actually drawing out the tree every time, this by far the hardest question I actually did here

>>4680582
not know my calc sorry

>>4680590
(pic related)
I did this a bunch of times with different equations, and I always got A (alpha) cancelled out. Yes, I saw the guy who bisected the triangle and shit he claimed that the two angles near "D" were 40 and 80 which add to 120 when they should add to 180, so clearly he's wrong somewhere. either way I couldn't get it to work out, may be impossible

>>4680661
impossible

>>4680667
I messed up and got 4, >>4681080 is right

>>4680682
=10-1+5+0
=9+5
=14

>>4680688
2D > 3D, dubs confirms

>>4680461
350
BEDMAS

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>>4680722
>>4680944
>>4681100
checked

>>4681111
G E T

>>4682155
>>4682377
checked

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>>4682613
fuck me i'm dyslexic,
The answer is negative five hundred and fifty.

wowe a moved threade from /a/ nice

Yep

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think about it hard, it's probably not the first answer you think off

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>>4682643

>>4682782
5!

Your fortune: Godly Luck

>>4682822
nope

>>4682839
5!

Your fortune: Bad Luck

>>4682845
correct!

>>4682795
hey unpass.

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I've only ever played the VN. Is the Steins;gate anime worth the watch?

>>4682894
it depends

>>4682899
dubs confirms
>>4682894
it depends

>>4682899
>>4682903
Thanks guys.

>>4682933
>33
your welcome

>>4680694
allready true

>>4682782
nothing cause the Bank got bankrupt and lost all my money

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>>4680462
0=12
Retarded nigger

>>4680482
Are you literally retarded?

tfw s4s is smarter than /a/

>>4683417
Did a thread on /a/ get moved here? Lol good job mods

>>4682782
15. U gotta spend some to make some.

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>>4683025
>>4683018
star butterfly I want to fucc you're 14yo alien ass

>>4680510
>plus > minus
Plus and minus have the same priority, which is important in some algebraic structures.

Average [s4s] users are like e^x. They can't integrate themselves.

>>4683814
I squared an iPhone to make it real.

(iPhone)2 = i2 * Phone2 = -1 * PhonePhone = -PhonePhone

>>4683814
I integrate e^x on a daily basis you're wrong f a m

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>>4680460
There is no solution.

If you say each side of the equation is a function (they are essentially 2 functions set equal to each other), then you can graph them.

Let f(x) = x - 7 and g(x) = 19 + x
When you set them equatl to each other, you are trying to find where the two lines intersect. In this case, they do not.

Try graphing f(x) and g(x) on the same graph. You will discover they are parallel lines. Each line has a slope of 1, but different y-intercepts (-7 for f(x) and 19 for g(x)).

The solution is not undefined or impossible, it just does not exist. There is no solution.

>>4683851
uhh what if they intercept in another dimension, don't you feel stupid now eh?

>>4683955
nice dubs