Please help me simplify this I keep getting the radicand as

>>37301018
sqrt(x^3*y^5)

>>37301018
x^(12/8)*y^(20/8)=x^(3*2*2/2*2*2)*y^(5*2*2/2*2*2)=x^(3/2)*y^(5/2)

>>37301094
This is correct. I don't understand why you'd think they're both 4 when it's x^12 and y^20. 12 and 20 aren't the same number. Are you retarded, OP?

>>37301018
>>37301043
>Write the radical as a fractional power:
(x^12*y^20)^(1/8) = (x^(12/8))*(y^(20/8))
>Simplify the fractions
12/8 = 4*3/8 = 3/8 and 20/8 = 4*5/8 = 5/2
>So we have:
x^(3/2)*y^(5/2) = (x^3*y^5)^(1/2) = sqrt(x^3y^5)

>>37301018
>came to this thread to laugh at you
>realized it's been so long since I used my brain that I can't remember how to do this

File: 20170526_225333.jpg (653KB, 2081x695px) Image search: [Google]

653KB, 2081x695px

>>37301094
>>37301112
Here is what my teacher says it's supposed to be. I'm trying to figure out how to get this answer.

Pls help me understand

>>37301134
Your teacher is on crack, that doesn't work.
(xy^2 (xy)^(1/8)^8 = x^8y^16xy=x^9y^17

>>37301134
Call your teacher a retard for me.

>>37301179
Thanks for the help anon
Original

>>37301134
Your teacher made a mistake. That 8th root should really be a square root. Otherwise it's the correct answer.

(x^12 * y^20)^(1/8)
x^(3/2) * y^(5/2)
(x^3 * y^5)^(1/2)
x*y^2 * (x*y)^0.5

>>37301018

Math major here

The radical simplifies as:
x^1.5*y^2.5