i'm a brainlet in math please help what is the answer and why?

Im drunk as shit and even I can figure it out

its c

Really, OP. Really. I haven't done math in 7 years and I figured it out. This is like pre algebra.

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help me please im originally retarded in math

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>>37074893
why is it c

i don't understand

>>37074848
Ok, I'll bite.

C, ma homie. It's the only one that doesn't multiply the initial 1000 with the photos, which, as they have nothing to do with each other, it's a pretty good start.

its a
orginal

>>37074848
Answer is C Because 1000 is initial cost. p is amount of photos and each photo costs 2 dollars so if we times the amount of photos by 2 we get the cost of the photos. the first 60 photos don't cost us anything so we subtract it before we multiply the amount of pictures.

>>37074925
this guy>>37074933

P being the number of photos and taking into account that the first 60 are free, you would need to subtract 60 to the number of photos taken to know how many photos you need to pay for, amount which you then multiply by 2 and add to the initial 1000 to get the total amount.

ITT: Retards
The answer is A, OP

>>37074848
the answer is C. Imagine they want 62 photos ($1004)
1000 + 2 * (62-60) = 1004

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>>37074933
>>37074948
fuck i am dumb, thanks guys i get it now

>>37074925
Okay here's the very basic function for calculating this:

A = B + C(x)

B = Original cost. Nothing affects this.
C = How much each photo will cost ON TOP of the original cost
X = the amount of photos bought
X - 60 because the first 60 were free

Therefor

A = B + C(x) turns into C = 1000 + 2(p - 60)

The answer is A because:
C = 1000p + 2
So the total cost is 1000 dollars multiplied by the number of photos which is p. then you add 2 because it's 2 dollars per photo

>>37074925
ok lets say you have 70 prints

under the first situation it would cost $7002

under the second situation it would cost $80000

under the third situation it would cost $1020

the third one is the only one that would make any sense

>>37074982
no worries m8.

Also, get the fuck out, you teenage filth.

good luck with your finals.

How're you liking middle school OP?

>>37074925
She must pay $1000 just to even be able to print photos. This $1000 fee includes 60 photos at no added cost. It's $2 for any more photos.

1000+2(p-60)

1000 for the fee
2(p-60) because you have 2 for "every photo minus the first 60", which were free.

(p-60) is how many photos you will have to buy out of the total, because the first 60 are free. (p-60) is actually a number, we just don't know what the value for p is yet, which is why we can't simplify it.

>>37075104
To add onto that, you should start thinking of "1000+2(p-60)" as a number. The idea of algebra is that you have an unknown number that you are expressing as variables and other numbers. When you simplify and expression you aren't actually changing what the final answer would be if you knew the value for the variable/s.

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>>37075009
>>37075010
>>37075104
>>37075193
thanks bros you've helped me a lot

It's C. Lol bruh you don't even have to think about the expression might be. You just have to think how the cost might look like after analyzing the two other variables. In this case 2 per photo beyond the first 60, well you're obviously going to have to substract the 60. Then multiply the value of p times 2.

>>37074848
The answer is C C C C C C C C C C C C C C C C C

>>37074848
It's c famalam

>>37075355
Why are you having difficulties with very basic algebra in the middle of may? Is this summer school to graduate or something

>>37074925
okay im fucking depressed hopefully i can make someone feel a bit better
most of the math is actually super simply, it just looks scary. if you go to a class and see 4 tables full of formulas it seems impossible. but as long as you start to pick up the parts and think of them as logical, basic things and can draw a comparison between an every-day thing and the formula, it becomes easy.
when it comes to this, you just need to think through.

so what do we know
the couple pays 1000 bucks which contains the shoot, and they get 60 free prints. so far all solution seems great because all of them contains the number 1000. so lets continue reading the task.
after the first 60 prints (which was inside the 1000 dollar price), the photographer asks 2 dollar/prints. this means, if i get 20 extra prints, thats 40 dollar extra. it will cost 1040 dollars, and i will get the basic 60 from the 1000 dollar stock price and 20 extra pictures i paid for 2 bucks each.

so lets see the solutions.
a, Cost = 1000 purchased + 2.
you can easily calculate this using the numbers from my example and see that it doesnt work. adding even just one more purchased picture would mean +1000 bucks, does not seem to real, right?

lets go to b,.
its a bit more complicated, but think about it.
when we look at this, we need to consider the last sentence of the task. (assuming at least 60 are puchased)
first, we should solve whats in the bracket, then multiply it by 1000.
but this would mean that the number of pictures purchased outside the 60 stock (because there is a -60) would be multiplied by 1000. sounds expensive and unrealistic, right? so if i buy 2 extra pictures, that would mean 1000(62-60) = 2000. this doesnt seem right either.

now we dont have any other options so c, must be right but lets think about it.
the first part of the equation is 1000 and it isnt multiplied by anything as a starter. this might seem good at the first look. but lets see the other part.

>>37075440
so the other part of the price is
2(p-60)
whats the p? all the pictures a couple will get. why is there a -60? because they already paid for it with the 1000 bucks price, which is the first part of the equation. whats the 2 part? a price for a single pic. so whats in the bracket, that means all the extra pic they asked for, and they cost 2 dollar each.

i know you can solve this by looking at it in a second if you experienced in math, but the point should be at these tasks to get used to thinking a bit.
you need to question why this, why that, why this isnt good and why is that great and tearing down the tasks to the most basic elements

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Wagies, i am honestly feeling sad that you don't have any intellect to speak of, at all. let me try to explain in children's terms:

y=b+mx

they even tee up the equation for you

charges 1,000 for the wedding (not a variable) = b
$2 per photo (not a variable/the slope of the line)) = m
x = p - 60 where
# of photos = p - 60 (defines the number of $2 photos that you purchase over 60)

>>37075562
he has to understand why c, is the correct solution in the first place, without that he cant make an equation that can easily used to illustrate the solution.
dont humblebrag with 9th grade math, what you do is the worst, scaring people away from math and acting smart over kiddie level stuff

C retard, this is basic order of operations shit they teach children

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>>37075715
explain that in a way that is easier to understand

this is NEETs giving back to the community

This guy has been posting one math homework question every 6 hours for the past 3 days.

The last one I read he posted it as an "IQ Test".

He's just getting /r9k/ to do his homework.

>>37076175
It's basic algebra shit so it's free (you)s for us. He's obviously an underaged ban or REALLY fucking stupid to be 18 and not understand algebra

>>37074925
At least 60 prints are bought. That's $1000. If the number of prints in total is p, the number of prints bought after the 60 mark is p - 60. But all prints purchased after 60 cost $2, so the total cost of the prints bought after 60 must be 2(p - 60). Add 1000 to that and you get C. Therefore the answer is c

homework thread is >>>/hm/

>>37074848
I refuse to believe that anyone 18 years or older could possibly be dumb enough to need help with this.

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Why are some mathfags are insufferable?

>feeling superior for knowing something before someone else so they're stupid

>>37076320
OP posted basic fucking algebra which everybody learns by 10th grade
4chan is supposed to be for 18 year olds
Do the math you weeb faggot.

>>37076320
That math is fucking easy I could do it in my sleep. I think OP is legit trolling/fishing for (you)s.

Someone help me with this:

If x2+4y2=40 and xy=6, what will be the value of x+2y?

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>>37076758
I thought you guys helped with homework

>>37076758
x = 2 and y = 3, so x + 2y = (2 + 6) = 8

>>37074848
answer is C

I-it really isn't... It isn't that hard to know why.

Are you retarded anon? serious question.

>>37076924
(cont)

okay, so ill explain it to you lad. So the initial cost is $1000, so nothing needs to be done with that number. P is the amount of photos that are purchased, so after 60 photos, P>0, and can be multiplied by 2 to make a outcome, so if you were to buy 72 photos, this is how the equation would look:

1000+2(p-60)
1000+2(72-60)
now you use BEDMAS or PEMDAS here
1000+2(12)
1000+14
1014
so C would equal 1014.

Need anymore help?

>>37077061

that's great that you read the thread and figured that out anon

you are 42nd

I'm I the only guy that can't do anything above simple math does this mean im retarded?

>>37074848
Answer is c. This is literally 10th grade curriculum in Alberta.

>>37077433
It depends why you don't understand it, math is a cumulative process.

>>37074848
this is advanced phd mathematics here in america. sorry, i don't know how to help you

>>37077558
Honestly it seems like to much work and it's extremely boring . I can't think of anything more boring then math.

>>37076758
Alright. Notice how the two expressions they give you can make up the square of x+2y.

Recall that x+2y squared is x^2 + 4xy + 4y^2.

You have xy. Multiply that by 4 to get 24. You also have x^2 + 4y^2, which is 40.

Add 40 and 24 and take the square root. You get either 8 or -8, which aligns with the possible values of x and y.

If you don't believe me, just check Wolframalpha.

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How do I do this one?
Can anyone walk me through how it's done?

>>37076758
z = (x + 2y)^2
z = (x + 2y)(x + 2y)
z = x^2 + 4xy + 4y^2

Group that as follows:
z = (x^2 + 4y) + 4(xy)

Just plug in the values you were given and you have:
z = 40 + 4*6
z = 40 + 24
z = 64

We started with:
z = (x + 2y)^2 = 64

Take the square root of both sides, remembering there are two possible roots (positive and negative):
x + 2y = +/-sqrt64
x + 2y = +/- 8

But we are told to consider x and y as positive real numbers, so we can ignore the negative value.

Answer:
8

>>37076868
This guy is an idiot, don't listen to him.
>>37076758
You either isolate x or y in the first and second equation. You'll get:
x = 20-4y or y = 5-.25x
and
x = 6/y or y = 6/x.
Now setting the equations equal to each other, you will get these two:
0 = -20[2(y^2)-y+3]
or
0 = -2.5(x^2)+5x-6
Then you substitute the values in the quadratic formula.
In both cases the answer will be an extraneous root, meaning it'll contain a negative root describable only as an imaginary number.
x = .25 +- 1.199i, y = 1 +- 1.183i
Solving x + 2y with these values you get 4 possible answers:
2.25 +- 1.167i
2.25 +- 3.565i
I'm too lazy to check if either x or y value works in the original equation, but those 4 values would be the possible answers assuming that all the 4 answers from the quadratic formula are applicable. You can also rewrite the answer as a negative radical jnstead of an imaginary number, so Sqrt(-3.565) or Sqrt(-1.167)

Seriously though this is like 9th grade algebra

>>37078012
>Seriously though this is like 9th grade algebra
And you managed to fuck it up and make it way more complicated than it needed to be, resulting in you getting the wrong answer.

See>>37078005
>>37077910

>>37078012
Fucking kek
>>37078005
Huh, how did you know we're only considering positive reals?

I didn't see a mention of that in his post. Am I missing something

>>37074975
OOOHH fuck i forgot you would have the number of p given to you so you would actually use parenthesis first instead of distributing.

>>37078035
Yeah, that's a brainlet way of going about it.

>>37078120
Except your answers were just wrong if you took 2 seconds to check them.

>>37078144
really if the word problem in the OP leads you to provide answers that include imaginary numbers, you should recognize immediately that you fucked up

i never took a math class past precalculus and even i realize that

>>37074848
It's C.
1000 + 2(p-60) basically means that the total costs are
>1000 dollars for the first 60 prints
>2 extra dollars for each additional photo ("p-60" is the number of photos minus the first 60 which have already been covered)

>>37076758
xy=6 means y=6/x or x=6/y
now replace one of them in the original eq and you shouldnt have problems after that

>>37078369
Doesn't work because plugging that into the other equation results in a mess that can't isolate for x or y. The question was solved a few posts ahead of you

>>37074848
Are you fucking kidding me?

It's C:
1,000 for prep and the first 60 prints, boom, done.
Now all you're worried about is what comes after the first 60 prints, and we already assume at least 60. Therefore, 2(p-60) make sense.

If p = 62, you only want to calculate 2 * 2, so 2(62-60) = 2(2) = 2*2.

Christ I hope you're underage or you may actually be retarded.