You should be able to solve this.

>>1508922
I'm asking /qa/ to do /qa/'s homework.

>>1508922
>homework
Looks like a typical contest problem to me. Homework looks like [solve problem by applying obvious method, no thinking required] for highschool and [prove easy theorem] for undergrad.

>>1509358
This isn't as easy as it appears on the first look. You probably need quite a bit of reasoning about ordering and size of terms.

Personally, I believe there's no solution. I have bruteforced all values for a, b, c up to 300 (and up to 1000 for small values of a) with no solutions.
The three numbers can't be equal (you would get a constant 3/2), therefore one number is always less than the other two (this also means one of the three terms has to be less than 1/2).
On the other hand, every number has to be smaller than the quadruple sum of the other two, so the numbers can't vary too much in size.

>>1511066
There are solutions, you cannot brute force them.

>>1508893
Get in terms of a common denominator, multiply all of them out, add like terms, figure it out from there. Don't feel like doing all that shit.

>>1511242
It's just that simple huh?

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You should be able to solve this.

>>1511250
Unless i'm missing something this seems like a really tedious exercise in nested functions, am I missing something?

>>1511666
It's surprising.

>>1511670
That didn't really help me.

>>1511674
Try a few iterations.
A(4,3) is when it gets really f u n.

>>1511682
No thanks, sounds just as tedious as I thought it would be.

>>1508893
i'm sorry I don't understand that picture. please use the one that substitutes the letters for fruit

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>>1511682
Even A(3,3) takes over 3000 steps to complete so bruteforcing isn't the way...

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>>1511704
https://en.wikipedia.org/wiki/Ackermann_function

I saw an article about it few days ago. The solution involved using elliptic curves and the answer had like 30 digits in it so you can't brute force it.

>>1511705
I was right! Didn't know it had a name though, interesting article.

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>>1508922
Lol, it's not homework, it's bait/nerd sniping

the actual solution requires graduate level knowledge of elliptical curves

https://www.quora.com/How-do-you-find-the-integer-solutions-to-frac-x-y+z-+-frac-y-z+x-+-frac-z-x+y-4/

>>1511819
My brain hurts.

>>1512146
Honestly the only difficult thing in that article is converting it to Weierstrass form, the rest you could probably wrap your head around with a wikipedia article on them.

up for smart people things

higer

>>1511250
>>1511704
>>1511705
die retards

>>1515817
*pulls down pants*

>>1516919
It's been a while since I saw bot-rofl bump a thread.

>>1517312
Dumb bot

Bump bot dude clearly noone has another trolly math problem to post so just stop bumping my thread
I'm sad about it, but if noone is interested what the fuck do you want?

>>1516926
>>1517324
http://desuarchive.org/qa/search/deleted/deleted/

Here you go, now please stop making these stupid posts. We all know that there's a bot bumping these threads. You can now go on with your lives.

>>1517483
But they didn't know about that one so I have to tell them.

Everyone needs to know about each and every stealth/bot bump and I'll make sure of it till the day they are all shut down.

hmm... it seems there is a mysterious force keeping this thread on the front page

>>1519272
Some mysteries are best left unsolved.

>>1519272
*rips off her clothes and rapes her*
heh, problemo solved

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I made this problem... kinda easy but i'm not very good at maths so I liked it.

>>1520049
by all positive integers n, i meant all positive integers n greater than 5... im dumb...

ok if noone wants to solve it thats fine too...

>>1520509
I'm thinking about it.

>>1520668
need some more time orrrr?

>>1522232
Hi bot-rofl, it's been too long since I pointed out one of your posts.

>>1508893
It reduces to this:

a^3 + b^3 + c^3 + abc = 3[ a^2(b+c) + b^2(a+c) + c^2(a+b) ]

So a relation between the cubes and squares of 3 variables. This looks like a job for some quadratic equation shit on steroids.
I'm out

>>1520049
I've been trying to brute force it and observe if there's a pattern that emerges, but I don't get a lot of solutions at low a,b,c.

>>1523159
Brute forcing isn't a proof, you fool.
How can you not do this its so fucking easy.

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You should be able to solve this.

>>1511819
Man, algebraic geometry seems so fucking cool, I just wish I could understand it better.

>>1523910
>How can you not do this its so fucking easy
nice try problem guy
still not going to try your shit problem

>>1523910
I said
>and observe if there's a pattern that emerges

>>1520049
Wait, I think I get it.
If (a,b,c) satisfies the equation, (ka,kb,kc) satisfies it as well, so that proves the infinitely many solutions part.
I'm too dump to show it doesn't have any solutions for n<=5, but I'd guess it can be reduced to >>1508893 and has really large solutions or something.

>>1524204
disregard this, im idiot

>>1524204
>>1524211
no, you're right, thats how you show it has infinitely many solutions as long at it has 1 solution, but you still have to show it has at least 1 solution for each n

>>1525412
Hey bot-age.

You just don't quit do you?

>>1523916
should I?

>>1523916
The first sentence says it's a month that entirely consists of days that are not unique (14, 15, 16, 17), which leaves July and August, as Bernard might know immediately if it were (June) 18 or (May) 19.
The day Bernard knows is shared with either May or June, because only that would remove all ambiguity to him (July vs August 14 wouldn't, and all days occur at most twice). So that leaves July 16, August 15 or August 17.
If the month was August, Albert still wouldn't know which of the two days was right. As he does, July 16 must be the correct birthday.