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IS THIS FOR REAL? v.2. Are Asians Superior now?

This is a red board which means that it's strictly for adults (Not Safe For Work content only). If you see any illegal content, please report it.

Thread replies: 154
Thread images: 26

File: asianv2.png (41KB, 527x377px) Image search: [Google]
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Previous thread hit bump limit.

>Be Chink
>Be in middle school
>pic related

Solve for shaded area
>>
8?
>>
come on /pol/ i believe in you
>>
>>138395493
42
>>
>>138395493
Well the area is somewhere above 32 and below what looks like 36
>>
>>138395493
post more pls
>>
>>138395493
48?
>>
>>138395493
>Are Asians Superior now?
Not empirically or historically, that would be whites and jews
>>
>>138395493
we could be doing the same shit, but our education system panders to the lowest common denominator. They're more concerned with making sure everyone feels included rather than really challenging students.
>>
How do you solve this? I suck at geometry
>>
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>>138395493
Your average chinese middle schooler isn't solving complicated integrals you fucking faggot.
>>
You are all retards

The answer is Viewtiful Joe
>>
>>138395493
Pi.radius squared.
Go nuts
>>
[email protected]
>>
>>138395493
32
>>
>>138395493
So why don't you go back to China?
>>
This doesn't look particularly difficult, is there a catch? You can figure out the radiuses of most of the circles involved and add/subtract.
>>
>>138395997
Pic related from previous thread
>shaded aread

/pol/ solved in ~200 posts
29.3
>>
>>138396353
>middle school
have you seen what our middle school kids do?`
>>
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>>138396380
dont kek me
>>
No idea, not relevant to my field and I was never educated on this.

t. Electrical engineering masters
>>
>>138396380
>>138396425
Yeah I've been in that thread, it's just that OP is being stingy with his geometry problems.
>>
>>138395493
It's not that hard, it's just quarter circles.
>Area of a circle = pi r^2
>start with biggest quarter circle and work down

Not going to waste 10 minutes on a middle school problem.
>>
Shit like this pisses me off.

I mean I know you're just supposed to assume that the curves are circular. But you don't actually KNOW that unless equations are provided.

ESTIMATE for the shaded area would be a better way to word it.
>>
>>138395493
wtf I hate doggos now
>>
>>138396117
>complicated integrals
>solving 4*4 and eyeballing an area
>>
>>138395493

Nike?
>>
>>138396117
you dont need integrals to solve that, retard
>>
>>138396414
I never went to middle school. So I'm guessing that's around age 14? I could do addition, subtraction, and multiplication by then. I also knew the formula for a fair number of geometric shapes including circles and quadrilaterals.
>>
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>>
>>138396117
this. though they aren't that complicated, just fucking tedious.
>>
>>138395493
This is fucking easy. All those arcs are quarter-circles; the radius for each is known. Why not make it challenging with some function generated arcs?
>>
>>138396515
>>138396632
Oh, right. Didn't realize it's perfect circle segments. Thought it were some arbitrary curves.
>>
>>138396656
yea you do if you want any sort of accuracy
>>
>>138396726
> I can totally do a backflip
> they're just tedious
> nah, I don't want to do one right now
>>
File: muhhcreativity.jpg (67KB, 800x528px) Image search: [Google]
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>>
>>138395493

start with area radius 12 quarter circle
>>
>>138396754
Show the solution step by step, senpai.
>>
>>138396107
It's deceiving at first . Just think of it as a lot of quarter circles and work your way from there. You don't need calculus.
>>
>>138396821
>i passed all my calculus classes, im not doing that shit for fun. fuck you.
>>
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>>138396781
the absolute state of burger education, at least tell me that you are of shitskin variety.
anyway wait a bit and some bored anon will solve it with nothing more complicated than pi r^2
>>
>>138396353
It doesn't say those are circles though so it's impossible to solve.
>>
>>138396905
> I can t-totally do it.
>>
>>138396999
I went to one of the top 100 school districts in the country and never handled anything akin to these problems.

Can you explain it?
>>
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>>138395493
>>
Solving maths problems /=/ You will have a better life
>>
>>138397217
t. guy who can't solve math problems
>>
>>138397123
ausie here did >>138396878
here we dont do such problems in school either but cmon, its not hard enough for you to be unable to see solution without doing this previously
>>
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waiting warmly for solution
>>
mathematician here. We're going to need double integrals and a third variable "t".

INT {INT { SQRT[pi*t^2]^3}dx}.

Good luck guys.
>>
>>138396632
fine i'll do it.
>144 pi/4 - 2.5*16 - 64 + 16pi - 4 pi +8 -16pi + 32

Whatever that equals. Don't have a calc on me.
>>
>>138397273
Some can't others can. If thats your thin than go for it but that doesn't mean you are superior.
>>
>>138396878
You're assuming the lines are tangent to all those 1/4 circles, and that all the boxes are 4 x 4 units.
>>
Jews own the west. THEY are the superior castes of our time!
>>
>>138397310
ougi = best girl
>>
>>138397359
step by step:
>biggest quarter circle has a radius of 12
>subtract pieces from that... which is what I did
when will you brainlets ever learn?
>>
The absolute STATE of western education
>>
>>138395493
There's probably missing something. I think you need some mathematical definitions of the curves / functions.
>>
>>138396632
Nah based on the coordinates you can figure out the curves. Then you can make an equation that adds up the difference

If it was multiple choice that would probably work but if you need an exact answer you would have to do a little work.
>>
>>138397404
t. inferior guy
>>
>>138397297
Huh, interesting. Thanks.

I was always aabominably terrible at mathematics, it's a wonder I graduated in the end.
>>
>>138395493

This is pretty basic-bitch shit, just create functions to represent the lines and integrate. Also

>Are Asians Superior now?

Lolno
>>
i see the halves of 4 ellipses that need to be added/subtracted. i don't remember if there are pythagorean tricks or geometric proofs that can solve for the shorter radii or if they can be eliminated by simplifying the equation.
>>
I was the poster in the last thread that was using algebra to solve the equation.

I worked out the previous answer and it was 100-(45Ï€/2) = 29.31625
>>
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>>138395493
https://www.youtube.com/watch?v=B_yNI3gAHNk
ezest math problem of my lyf
>>
>>138397702
>>138396380
>>138396425
>>
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>>138395493
did I do it right anon ?
>>
>>138396878
You're forgetting this is 4chan and you need to spell out every single detail of a problem people will make up assumptions in order to come up with the most incorrect answer possible.

You can post a picture of two scales and ask "Which is heavier, a kilogram of steel or a kilogram of feathers?" and people will say
>GUYS WE CAN'T ASSUME THE LOCAL GRAVITY IS EXACTLY THE SAME ON BOTH SCALES
>>
I could probably do this in middle school when I did math all the time. No way in hell I'll do it now though lol
>>
>>138397799
My post in the last thread
>>138390292
>>
File: Untitled2.jpg (51KB, 910x979px) Image search: [Google]
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same principle as previous
>>
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Can't be bovered to use a calculator
>>
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>>138396580
me too
>>
>>138396380
the answer is 32pi - 64
>>
>>138398191
don't forget to subtract 15 for tyrone.
>>
>>138397722
Thanks anon. Getting the segment by subtracting the right triangle was the part I was missing.

Easy to do geometrically once you realize that.
>>
>>138395493
i'm an asian
((pi*8^2)/4 - (8^2)/2) - (4*pi - (4^2)/2) + ((pi*12^2)/4 - (12^2)/2) - ((pi*8^2)/4 - (8^2)/2)
>>
>>138398434
shit and you wonder why you can't get laid.
>>
I just used the application for it nerds.
>>
>>138398151
And how do you know it's exactly quarters of circles and not some random curves?
>>
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>>
>>138398434
>not factoring out the constans
Omuich can't compete with REAL asians.
>>
>>138398191
can confirm, did something similar
36pi - 64

too easy, op
>>
>>138395493
Just find the semicircles area from the curves, reverse it to the total 12*12, and you will find it, brainlet
>>
>>138395493
I thought this thread was for politics and not for fucking math problems. If you're gonna shill for the asians, at least bring up a point better than "they do harder math in school."
>>
>>138398652
https://www.youtube.com/watch?v=B_yNI3gAHNk
It says in the video where the problem was shown, which faggot OP didn't give us because he wanted to mess with us
>>
>>138398970
ok
>>
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>>138398925
> mad cuz he can't do math
> lashes out instead of learning
>>
>>138398925
>>138396699
>>138396822
discuss
>>
>>138395493
>be illiterate communist leftyfaggot
>do my math homework /pol/

fuck off to /leftycuck/
>>
>>138396781
No you don't just divide into quarters of circles add and subtract these.
>>
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>>138395493
ITT angry snow niggers that don't like being told they're stupid
>>
>>138395493
Is that a bad dragon dildo?
>>
quick approximation:

113568 total pixels in the mainsquare.
25846 red pixels

Total area of the main square: 12*12 = 144
Percentage red: 25846/113568 = 0.22758

22.7% of 144 is : 0.22758*144 = 32.77152

Therefore the area of the red zone is approximately 32.77
>>
So this one is pretty easy when you recognize the quarter segments...unless I'm missing it, the other problem was much harder and there was no quarter segment trick. Only brute force answers were found, no clean expression involving pi (29.27625)
>>
I thought we invented computers so that we wouldn't have to deal with this kinda shit anymore.
>>
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>>138399794
No; it's ~36.53. You fucking killed all the astronauts.
>>
>>138399945
The computer can't do it without an Asian telling it what to do.
>>
>>138400104
They are the niggers of electronics if you will.
>>
"show your work bitches" --your algebra teacher
>>
>>138398191
>>138398249
>>138398434
>>138398798
32Ï€-64 is the correct answer
>>138399794
Your pixel approximation was a bit off.
36.53088
>>
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>>138395493
I think you can solve it with out calculus by thinking of it as four overlapping circles, to which you can take the area of all the circles due to your knowledge of the radius based on the square, then divide the areas by four, due to the overlap only being 1/4 of a circle, eventually just take the difference of each circle and the answer should be really damn precise, even though I'm assuming they're perfect circles.The last thing to do is take in notice of the area (left bottom corner) where both areas overlap, so to correct that, just take the area of the square of both circles( a.- radius=8 and b.- radius=12) divide by four, the difference of circle and square, and add up the shaded areas but subtract your previous answers to get rid of the overlap space getting counted twice.
>Be me
>Be white
>Make math run through your veins
>Be lazy enough to give the whole explanation on how to solve it, but don't do the calculations yourself.
>>
File: 1503270513079.png (49KB, 527x377px) Image search: [Google]
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>>138395493
You start out with the 9x9 grid all white. Then, you fill in figure 1 with red. Fill in figure 2 with white. Fill in figure 3 with red. Fill in figure 4 with red. Fill in figure 5 with white. Each square has length 4, so the area of the red figure is pi*(8^2) - pi*(4^2) + [8^2 - pi*(8^2)] + 4^2 - [12^2 - pi*(12^2)] = pi*128 - 64.
>>
>>138399945
These problems are arbitrary and have no exact real world use, but they use the same brain functions as IQ tests. Being able to see patterns and make sense of shit in your head is what makes the alphas better than you.
>>
>>138396999

pi are squared? pi are round you dummy!
>>
>>138400420
You can solve it with geometry.
>>
>>138400425
shit, i forgot to divide by 4, its pi*32 - 16
>>
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>>138400727
Yeah pi squared is just fucking cobbler, dumb europoors.
>>
>>138400757
Yeah that's what I did, but geometry has a major flaw, you always assume shapes are perfect even if they look perfect, e.g. How can you differentiate a polygon with 999x10^99 sides, from a circle?
>>
File: 20170821_020155.jpg (163KB, 992x559px) Image search: [Google]
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>>138395493
shouldn't this work too?
>>
File: Solution.png (39KB, 451x375px) Image search: [Google]
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Just rotate the thing and stop beign dumb
>>
>>138395493
t. crowdsourcing for chinese school students maths problems
>>
>>138400425
pi*(8^2)/4 - pi*(4^2)/4 + [8^2 - pi*(8^2)]/4 + 4^2 - [12^2 - pi*(12^2)]/4 = pi*16 - pi*4 + 16 - pi*16 + 16 - 36 + pi*36 = pi*32 - 4.
>>
File: ken wheeler .jpg (196KB, 720x922px) Image search: [Google]
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>>138395493
ken wheeler is superior
>>
>>138401204
actually results in 36.54
>>
Pretty interesting problem but assuming they have done similar problems is not very hard. It only seems complex because people haven't solved a similar problem before.
>>
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>>138398191
/pol/ math god confirmed? Wowwwwhh.
>>
>>138401713
We antigravity soon
>>
>>138395999
I too got 48
>>
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My black friend sent his novel solution to me. I think we may be seeing a revolution in mathematics soon with minds as great as his.
>>
>>138399946
>got a good estimate in less than 2 minutes of work.

>>138400278
>Your pixel approximation was a bit off.
meh, forgot to include the black pixels inside the figure. Also I could have cropped the image better and fine tuned the threshold for the red color.

Oh well..
>>
>>138401698
no, wait, its pi*(8^2)/4 - pi*(4^2)/4 + [16^2 - pi*(8^2)]/4 + 4^2 - [24^2 - pi*(12^2)]/4 = pi*16 - pi*4 + 64 - pi*16 + 16 - 144 + pi*36 = pi*32 - 64
>>
>>138396548
>I mean I know you're just supposed to assume that the curves are circular. But you don't actually KNOW that unless equations are provided.

This.

There must be a note included with this problem stating that all the curves are perfect quarter-circles, otherwise all answers are simply guesses and estimates.

But if there is a note, then the note itself serves as a hint, because then the students know the they must look at the problem in terms of areas of the circles.

Also, their teacher already most likely showed them how to approach such problems as they probably did several examples in class. Students anywhere would be able to do it if they were taught how, if our schools did not pander to black and Mexican kids.
It is doubtful that these Asian kids just came to class one day and the teacher presented them with this problem and expected them to solve it without ever having seen anything similar.
>>
>>138403641

Yeah assuming that they are all perfect quarter circles then the answer is:

36.36955169747006

See the following code:

from shapely.geometry import Point, Polygon

A = Point(0,12).buffer(12).intersection(Polygon([(0,0), (0,12), (12,12), (12, 0)]))
B = Point(4,12).buffer(8).intersection(Polygon([(4,4), (4,12), (12,12), (12,4)]))
C = Point(8,0).buffer(8).intersection(Polygon([(0,0), (0,8), (8,8), (8, 0)]))
D = Point(8,4).buffer(4).intersection(Polygon([(4,4), (4,8), (8,8), (8, 4)]))

c1 = A.difference(B).difference(Polygon([(0,4), (0,12), (4,12), (4,4)]))
c2 = c1.difference(Polygon([(0,0), (0,8), (8,8), (8, 0)]).difference(C))
c3 = C.difference(D)
c4 = c2.union(c3).difference(Polygon([(0,0), (0,12), (12,12), (12, 0)]).difference(A))

c4.area
>>
>>138404076

Also WTF is this doing on /pol/ anyways? No way this leads to any productive discussion.
>>
>>138395493

8.25
>>
68.0625
>>
>>138404447
>>138404658

What the fuck are you doing?
>>
>fucking time wasting Sudoku tier puzzles should be taught everywhere
>this is what we should teach instead of actual mathematics


Pure liberal arts scum
>>
shill thread faggots

blm guy is going to come in and solve it and tell you how dumb white people are
>>
>>138395493
The thing is, they are taught how to solve this before they are asked to solve it.
It isn't a good comparation to just dump it into /pol/ and expect everyone to know how to do it.
>>
>>138404966
It's solvable with simple set theory, see: >>138404076

>>138405043
Fuck BLM and shills, I beat both of them to it.
>>
>>138396878
This, and I'm a fucking burger. Come on guys.
>>
>>138396078
So true. White boi here who should have been doing algebra in the 2nd grade but I was stuck waiting for Jamal to learn fractions and decimals for 6 more years! Fuck public burger edu
>>
>>138399946
How are you gonna get off the planet? You saw what just happened to the astronauts.
>>
>>138406397
Pretty much this. "No Child Left Behind" = "All Children Dumb As Fuck"
>>
>>138405043
>m-muh shills!
kys
>>
>>138395908
this guy gets it
>>
>>138395493
i dun noe man i keep squinting and it doesnt come to me. .. 2 and 1/4 4x4 squares ?!?! idk what do you want from meh
>>
>>138398664
THE ONLY FUCKING GOOD METHOD
all these pathetic plebians ITT
>>
We can assume they're all circular arcs. But it's tricky.

First of all, make the graph size 1 rather than 4. Multiply the final answer by 16 at the end to undo this.

To find those areas between two arcs, consider centering the smaller arc at the same center as the larger arc. Then the total area between is

pi (r0^2 - r1^2)

Now consider what happens when we slide the smaller half-circle to the edge (say the right) as shown. The same total area is preserved. But on the left there's more area and on the right there's less. This is easy for the smaller (vertical) pair where one has radius 2 and the other has radius 1. On the bottom the smaller isn't at all, so the area on the bottom is

pi r0^2 / 2

and the area on the top is

pi r0^2 / 2 - pi r1^2 where r0 = 2 and r1 = 1.

Then divide all that by 2 again because you're just looking at the left side, and you get

pi / 2.

It's harder for the two larger circles (horizontal) because when you slide the smaller all the way to the right, there's still some left on the left. Maybe the trig works out easy.

Then how to fix up the lower left corner and avoid double counting it.
>>
>>138396425
>>138395493
It takes 2 pieces of knowledge, finding area of a circle based on radius length, and common addition subtraction. That's it.
>>
>>138398664
More or less what I did, but dealing with the lower left corner still requires attention.
>>
>>138408257
What the fuck... either use a smart trick like >>138398664 or don't fuck around and set theory it in place like >>138404076

>>138408418
Also need the square root of 2 to help with the truncated bits. But yeah pretty much just that.
>>
>>138408630
The "smart trick" doesn't solve the problem in the lower left. It's just a visual of what I calculated.

And the "set theory" is code that gives a numerical answer, what should be wanted is something with integers and pi.
>>
>>138408840
You cannot express it just in integers and pi, you also need square root of 2.

What is this lower left problem you speak of?
>>
1 solution is integrals
>>
>>138396699
>M
>V
Male/Vagina?
>>
>>138401247
Holy shit I didn't see that
>>
>>138398151
honestly this is most reasonable
>>
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>>138395493
This board is 18+. sage
>>
>>138395493
Somewhere around 40
>>
extreme case
most of the schools arent that hardcore
>>
>>138395493
Its not actually that hard

you just need to have a 3x3 quarter circle minus a 1x1 square minus a 2x2 quarter circle minus a 2x2 square plus a 2x2 quarter circle minus a 1x1 quarter circle

= ( 9/4 pi) - 1 - (pi) - 4 + pi - (1/4 pi)
= 2pi - 5
=1.28


probably messed something up though
Thread posts: 154
Thread images: 26


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