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Series-Parallel Circuits 2017-03-29 01:29:02 Post No. 16922401
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Series-Parallel Circuits 2017-03-29 01:29:02 Post No. 16922401
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File: FireShot Capture 1 - Series-Parallel Circuits_ - https___njraritanvcc.electude.com_s.png (75KB, 1280x694px) Image search:
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Hey /o/ I'm in class and my class has been given the task of going through this section of electrical.
We don't have the option to do Parallel Circuits and were sent straight to Series-Parallel.
I was hoping someone or more of you could lend some help or advice to a studying tech.
Thank you
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>>16922401
1/Rv=1/R2+1/R3
1/Rv=1/100+1/25
1/Rv=1/100+4/100=5/100=1/20
Rv=20 Ohm
Rt=Rv+R1
Rt=20+20=40 Ohm
I=U/R
U=30V
R=40 Ohm
I=0.75 Amps
Now git out.
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Are you saying the answer was/is 0.75? Our teacher is stuck on the idea that we went over this stuff yesterday but we stopped after Series Circuits and haven't been over Parallel Circuits at all yet so he won't help or let us work together haha
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>>16922555
If you can't figure out what the answer is based on what's posted in >>16922435, you're either stupid, underage, or both.
Regardless, get out.
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Just asking for clarification haha we just started our section for Electric and figured I'd ask. I'm going to sit down with it and figure it out, was just asking. I'll get out now haha, thank you
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>>16922555
It tells you how to do it in the picture my dude. Are you an illiterate? A thread died for this.
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They literally explain it to you in the picture.
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Feels bad
Wrote it out and i get it...
Sorry, and thank you everyone, Ill get out and stay out
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>>16922608
I have an actual answer for you. I'll post the picture and explanation in a minute.
>>
File: series-parallel.jpg (169KB, 830x1110px) Image search:
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>>16922608
>>16922617
1) Convert R2 and R3 to one equivalent resistor. The formula is 1/Req = 1/R2 + 1/R3. If you have just two resistors, such as this case, you can also use the formula Req = (R2 * R3) / (R2 + R3).
Your Req in this case is 20.
2) The current going through your Req is equal to the sum of the currents going through R2 and R3. Since R1 and your Req are in series, the current going through R1 and Req is the same. Find the current going through these resistors.
I = 30 / (20 + 20) = 0.75A.
3) Now you have to go back to your separate resistors, R2 and R3. The total current through both of these resistors adds up to 0.75A. The current going through each resistor is related to its value. The bigger resistor has less current going through it. The current going through R3 is:
I * ( R2 / (R2 + R3)) = 0.6A.
The current through R3 is 0.6A.
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>>16922401
On an unrelated note. I used ARGO last year for my apprenticeship school training and it's better than our textbook. Seriously do as many lessons as possible even stupid things like operation of a shock absorber
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