>band has 1-1x0+3/3 drummers

>band has 0 drummers

wtf are you talking about

>>70210104
It's 2, though you could see it as 4/3 if you did the math wrong. I don't know how you got 0.

>>70210069
Where's your parentheses nigga?

>>70210240
Nice bait.

>>70210259
not needed if you understand pemdas

>>70210240
it's zero retard

>>70210069
Name exactly 57 bands with 2 drummers

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>>70210069
>band has -1/12 drummers

>>70210283
>1+1=0

It's 2
>1-1x0+3/3
No parenthesis or exponents
>1x0 = 0
>3/3 = 1
Now we have 1-0+1
>1-0=1
>1+1
>2

>>70210350
the fact that you even have to say this is really something

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Amount of drummers equate to the solution of the Riemann Zeta function of 2

>1-1x0+3/3
>-1x0=0
>3/3=1
>1+1=2

>>70210407
>1+1=2

>>70210350
lmao nerd

isnt 1-0 = 0 though ?

>>70210069
>using x to signify multiplication
underage

>>70210311
I know what this number is and im scared of it

>>70210415
2+2=5

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>>70210395

>band has sqrt(-1) members
Meme magic

1-1=0
0×0=0
0+3=3
3/3=1

How is that so hard?

>>70210501
he didn't explicitly state whether it's supposed to be x or * and he didn't have to because both of them work here.

>>70210069
1-1x0+3/3=0
1*x=x
x*0=0
1-(+3/3)=0
1-1=0

>>70210696
>1-1x0+3/3=0
what did he mean by this?

>>70210350
the point of these threads are to bait each other with bad math

>>70210471
good one

>>70210069
>band has -1*(1+sqrt(-π^2)+(sqrt(-π^2))^2)/2+(sqrt(-π^2))^3)/6+(sqrt(-π^2))^4)/24+(sqrt(-π^2))^5)/120+...) drummers

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>>70210696
>1-(+3/3)=0

>>70211610
3/3 = 1
1-1=0

tards
1-1x0+3/3
1-1=0
=0x0=0
3/3=1
1+0=1
baka americans

>>70210539
>=5

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>band has qtπ drummer

>band has sqrt(81)(sin2x+sin2y)/4.5 drummers

>band has 1x1 drummers
Only fa/tv/irgins will understand this reference

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>>70210069
>ensemble has [ζ(3)]/|Aut(A_4)|*ϑ(π/2i) conductors

>>70212092
I'm sorry to hear that desu

>>70210415
Hi Terrence

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>band has root 2 drummers