Can you solve this math problem?

>>78219519

no ty

1/2, because there are two cards with at least one red side, so you can assume you've picked either red/blue card or a red/red card.

>>78219519
2/3. If it already known that the back of the first card is red, so the chance that another side is blue is 2/3, because only 2 cards in deck had red back and one side of this cards is already known.
If we didn't know that the first card back is red, then it would be 1/2 * 2/3.

>>78219519
2/3

>>78219578
Sorry for mistakes, I just woke up, don't even see the phone's keyboard normally, but I could not walk away from anon in need of help.

>>78219519
3/5…is the number of math classes I've failed

>>78219519
1/2

how solve this problem nip:
you are tasked with selecting the card with red on both sides

you are only allowed to draw one card and look at one side but you can put it back and redraw as many times as you want before making your final choice

how do you go about doing this

what do I get in return if I tell you the answer?

>>78219838
Proof of your superiority

>>78219519
Not again this problem...

There are three blue sides and three red sides.
So the odds to pick a certain red side are 1/3.
So the odds you picked the red side in the same card as a blue side are 1/3.

>>78219519
i can
but i won't

File: prooo.png (7KB, 677x342px) Image search: [Google]

7KB, 677x342px

2/3 it's red, 1/3 it's blue

fuck thinking when ruby exists


cards = [[:red, :red], [:blue, :blue], [:red, :blue]]
count, n = 0, 100000

n.times do
roll = [1,1]
while cards[roll[0]][roll[1]] != :red
roll = [rand(3), rand(2)]
end
roll[1] == 0 ? r = 1 : r = 0
count += 1 if cards[roll[0]][r] == :red
end

p count/n.to_f

File: 20170812152317.png (4KB, 506x97px) Image search: [Google]

4KB, 506x97px

>It's 1/3.

we select one card from box with one certain side upon. Each card have 2 condition, then we have 6 conditions at all.

Already know one side is red, it's condition 1&2&5.
we can see only condition 5 offer a blue side.
P(another side is blue ) =1/3

It's 1/3, I think, since you already said that red is the color seen on the card that is picked and, out of the 3, one is 100% blue.

Who is she btw?

1/2 because it's definitely not the purely blue card since it has no red side and there's one fully red card and one blue and red card

I don't know where people are getting 1/3 and 2/3 from

>>78222449
See >>78220995

my dick was in the box

>>78222755
tfw no dick?